The solution to the problem is as follows:
let y = asinx + bcosx
<span>
dy/dx = acosx - bsinx </span>
<span>
= 0 for max/min </span>
<span>
bsinx = acosx </span>
<span>
sinx/cosx = a/b </span>
<span>
tanx = a/b </span>
<span>
then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) </span>
<span>the max/min of y occurs when tanx = a/b </span>
<span>
then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) </span>
<span>
y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) </span>
<span>
= (a^2 + b^2)/√(a^2 + b^2) </span>
<span>
= √(a^2 + b^2)</span>
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Standard form is
ax+by=c
where a and b and c are integers
and a is normally positivie
y+1/5=3x
minus 3x both sides
-3x+y+1/5=0
minus 1/5 both sides
-3x+y=-1/5
times -5 both sides
15x-5y=1
not listed
There are 36 different possibilities for his lunch.
We can use the fundamental counting principal to solve this problem. We simply need to find the number of options for each part of the meal and multiply them.
Sandwich = 3
Snack = 3
Dessert = 2
Drink = 2
3 x 3 x 2 x 2 = 36
g(x) = -(x + 1)^2 - 3
Let's simplify this equation
g(x) = -(x^2 + 2x + 1) - 3
Distribute the negative sign
g(x) = -x^2 - 2x + 1 - 3
Combine like terms
g(x) = -x^2 - 2x - 2
The value of a = -2 and this value is LESS THAN 0
Answer:
1.1
Step-by-step explanation:
1 in probability means always so anything greater than 1 is meaningless
