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Archy [21]
2 years ago
12

When expressing sets, you may write "inf" for infinity and "U" for union.

Mathematics
1 answer:
GarryVolchara [31]2 years ago
3 0

Answer:

The complement of the given set in interval notation is(-\infty,-5]\cup(6,\infty). It can we written as (-inf,5]U(6,inf).

Step-by-step explanation:

The given set in interval notation is

(−5,6]

It means the set is defined as

A=\{x|x\in R,-5

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.

Here, universal set is R, the set set of all real numbers.

U=\{x|x\in R\}

The complement of the given set is

A^c=U-A

A^c=\{x|x\in R,-\infty

Complement of the given set in interval notation is

A^c=(-\infty,-5]\cup(6,\infty)

Therefore the complement of the given set in interval notation is(-\infty,-5]\cup(6,\infty). It can we written as (-inf,5]U(6,inf).

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Nina [5.8K]
237 is the answer because 200+30+7 if you add that up together you will get 237
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2 years ago
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Two more than four times a number is the same as 6 more than twice the number find the number ​
Yuki888 [10]

Answer:

The number is 2. :)

Step-by-step explanation:

4x + 2 = 2x + 6

    -2            -2

4x = 2x + 4

-2x   -2x

2x = 4

/2    /2

x = 2  

7 0
2 years ago
Please answer this correctly
aleksklad [387]

Answer:

63.2 = y

Step-by-step explanation:

The perimeter is the sum of all the sides

P = 7.8+ y+37.6 + y

171.8 = 7.8+ y+37.6 + y

Combine like terms

171.8 = 45.4 + 2y

Subtract 45.4 from both sides

171.8-45.4 = 45.4 + 2y -45.4

126.4 = 2y

Divide each side by 2

126.4/2 = 2y/2

63.2 = y

6 0
2 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
2/5(6-5p)=? simplify the expression​
beks73 [17]

Answer:

12/5 - 2p

Step-by-step explanation:

Use the distributive property:

2/5 * 6 - 2/5 * 5p = 12 / 5 - 2p

3 0
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