In order to sole the problem you need to create an equation to model what you are trying to do.
You end up with an equation looking like
25000*0.95^t
25000 is the starting value when t=0
95% is the amount remaining after the 5% decay
0.95 is being raised to the power of t to determine how many times it has decayed
When t=3 the equation should be
25000*0.95^3=21434.375
Answer:
Step-by-step explanation:
f(5)=49.5(0.88)^5
f(5)=$26.12
Answer:
6n^4-10n^2+10n
Step-by-step explanation:
4 n^4+2n^4-3n^2-7n^2+9n+n
6n^4-10n^2+10n
|-3|=3 right?
Then it is
3*-6=-18
To find one year, here's the equation:
5000 + 0.06(5000)
For 10 years:
5000 + 10(0.06(5000))
Multiply:
5000 + 0.6(5000)
We can make it smaller:
1.6(5000) = 8000
You can make $8000
