Answer:
a.x=39.2
b.Use whole wire as a circle
Step-by-step explanation:
We are given that
Length of piece of wire=70 units
Let length of wire used to make a square =x units
Length of wire used in circle=70- x
Side of square=
Circumference of circle=
Combined area of circle and square,A=
Using the formula
Area of circle=
Area of square=
a.
Differentiate w.r.t x
x=39.2
Again differentiate w.r.t x
>0
Hence, the combined area of circle and the square is minimum at x=39.2
b.When the wire is not cut and whole wire used as a circle . Then, combined area is maximum.
Answer:
560m³
Step-by-step explanation:
Cuboid : length = 16, width = 5, height = 4
Prism : base = 16, perpendicular height = 6, height = 5
V = volume cuboid + volume prism
V = 16 x 5 x 4 + (16 x 6 : 2 x 5) = 560m³
I will come back to this when I am older
The rule for multiplying similar bases with exponents:
(a^b)(a^c)=a^(b+c)
In this case we have:
(5^-2)(5^-1)
5^(-2-1)
5^(-3)
The rule for negative exponents:
a^(-b)=1/(a^b)
So in this case:
5^(-3) is equal to
1/(5^3)
1/125
Answer:
x-intercept (2,0) or x=2
y-intercept (0,-4) or y=-4
Step-by-step explanation:
4x-2y>8
2x-y>4
2x-4>y
y<2x-4
y=2x-4
when y=0
2x=4
x=2
x-intercept is (2,0)
and y-intercept is (0,-4)
put x=0,y=0
0-0>8
or 0>8 which is not true. so (0,0) does not lie on the graph.
so graph lies right of the line .
