Answer:
I dont think you have included the whole question please do so
Step-by-step explanation:
Answer:
ΔABC ~ ΔEDF; x = r × w/z
Step-by-step explanation:
m∠ABC = 180 -47 - 62 =71 = m∠EDF
ΔABC ~ ΔEDF
w/z = x/r
x = r × w/z
<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>
Answer:
4a-9 ÷ -19
Step-by-step explanation:
(It was easier for me to put it in fractions)
+
+
(3-a) (a-4) + (5-a) (a-3)
+
+
3 - a · a - 4 + 5 - a · a - 3
+
+
3 - a + 1 - a - 3
1 - a - a
1 - 2a


Answer:
a) 0.19
b) 0.9689
c) ≈ 6 cars
Step-by-step explanation:
Rate at which cars arrive = 12 cars/hour = 1/5 cars/minute
time needed by each car to complete ATM transaction = 6 minutes = 1/6 car/minute
capacity of lane = 10 car
n = 10
<u>a) Calculate the probability of an arriving not using the ATM because the line is full</u>
p ( not using the ATM ) = 0.19
<u>b) probability that a car will not be able to use the ATM machine immediately on arrival</u>
P ( n > 0 ) = 1 - Po
= 1 - 0.0311 = 0.9689
<u>c) Average number of cars in the lane </u>
Lq = 5.74 ≈ 6 cars
attached below is the detailed solution
Answer:
Step-by-step explanation:
the answer is six you divide 18 by three and boom