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2 years ago

What is the common ratio for the geometric sequence?

Mathematics

1 answer:

Bezzdna [24]2 years ago

6 0

Answer:

3 is the correct answer

u can find common ratio by dividing a specific term in GP by its preceding term. ...just as here

4/(4/3) = 3

also 12/4 = 3

also 36 /12 = 3

hence the common ratio for this GP is 3

hope it helped

Step-by-step explanation:

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Jeanne makes hair bows to sell at the craft fair each bow requires 5yards of ribbon at the fabric store ribbon is sold by a foot

Karolina [17]

Answer:

1260

Step-by-step explanation:

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3 years ago

Destiny poured 24 ounces of juice into 4 1/2 ounce servings. She has 1 1/2 ounces of juice left over. How many 4 1/2 ounce servi

Nataly_w [17]

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3 years ago

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Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

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3 years ago

In the interval 0 x 360 find the values of x for which cos x =0.7252

Sergeeva-Olga [200]

Answer:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

Step-by-step explanation:

We have a positive value for the cosine of x, so we know that the value of x should be in the first quadrant (0 ≤ x ≤ 90) or in the fourth quadrant (270 ≤ x ≤ 360).

Now, let's find the value of x that gives cos(x) = 0.7252 using the inverse function of the cosine, that is, the arc cosine function.

The value of x can be calculated using:

$x = arccos(0.7252)$

Using this function in a calculator (you may find it as: $cos^{-1}(x)$ ), we have that:

$x_1 = 43.5145\°$

So this is the value of x in the first quadrant. To find the other value of x, in the fourth quadrant, that gives the same result, we just need to calculate 360° minus the value we found:

$x_2 = 360\° - 43.5145\° = 316.4855\°$

So the values of x are:

$x_1 = 43.5145\°$

$x_2 = 316.4855\°$

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2 years ago

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Answer:

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Step-by-step explanation:

h(3) = -16(3)² + 70(3) + 95 = 161

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2 years ago

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