The incorrect step is ln(x²) = ln(3x/0) because ln(x/y) = lnx - lny and the solutions are x = 0, 3
<h3>What is a logarithm? </h3>
It is another way to represent the power of numbers, and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
2ln(x) = In(3x) - [In(9) - 2ln(3)]
In(x²) = In(3x) - [In(9) - In(9)]
ln(x²) = ln(3x) - 0
ln(x²) = ln(3x/0) (incorrect step)
ln(x²) = ln(3x)
x² = 3x (correct step)
x² - 3x =0
x(x - 3) = 0
x = 0, 3
Thus, the incorrect step is ln(x²) = ln(3x/0) because ln(x/y) = lnx - lny and the solutions are x = 0, 3
Learn more about the Logarithm here:
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Answer:
The number of cups = 8 ....
Step-by-step explanation:
Let x be the number of cups
Let y be the number of plates
According to the given statement:
y=2x-4 This is equation 1
Now,
60% = 0.60
y=0.60(x+y) This is equation 2
Now substitute equation 1 in equation 2.
y=0.60(x+y)
2x-4=0.60(x+2x-4)
2x-4=0.6x+1.2x-2.4
Solve the like terms:
2x-4=1.8x-2.4
2x-1.8x=4-2.4
0.2x=1.6
x=1.6/0.2
x= 8 cups
Therefore the number of cups = 8 ....
Answer:
30 miles per gallon
Step-by-step explanation:
I jus Done this one
Answer:
Sometimes
Step-by-step explanation:
I’ll give you an example so you can understand:
Let’s say x is 4. So plug 4 into the problem:
|4|=4 → This is a very true statement, where the absolute value of 4 is equal to 4.
Now, let’s say x is -7. So plug -7 into the problem:
|-7|=-7 → This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.
So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x <u>sometimes.</u>
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Hope this helps and answers your question! :)
It is obvious that the radicals with negative sign tends to be less than those that are positive. So from there you already know a basic order. Now to be sure, you can use a calculator or just solve by squaring the whole number to find the radical form.
