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Mashutka [201]
3 years ago
11

Write the expression for the following situation: Roger has 5 toy cars. His sister gives

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0
5 + x
This shows the total of Roger’s toy car plus what his sister gives.
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Given h(x) = -5x + 3, find h(5).
cluponka [151]

Answer:

h(5) = -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -5x + 3

h(5) is x = 5

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function]:                                                                                h(5) = -5(5) + 3
  2. Multiply:                                                                                                             h(5) = -25 + 3
  3. Add:                                                                                                                   h(5) = -22
8 0
3 years ago
Suppose a random variable X has the following probability density function:f(x)=1/x, 1≤x≤C, or f(x)=0 otherwise a) what must the
Sergeeva-Olga [200]

Answer:

a)  C=e^1=e

b) P(X

c) E(X) =\int_{1}^e x \frac{1}{x} dx =x \Big|_1^e \ =e-1

E(X^2) =\int_{1}^e x^2 \frac{1}{x} dx =\frac{x^2}{2} \Big|_1^e \ =\frac{1}{2}(e^2 -1)

Var(X)=E(X^2)-[E(X)]^2= \frac{1}{2}(e^2 -1) -(e-1)^2 = 0.242

Step-by-step explanation:

a) what must the value of C be so that f(x) is a probability density function?

In order to be a probability function we need this condition:

\int_{1}^C \frac{1}{x} dx =1

And solving the left part of the integral we have:

ln(x) \Big|_1^C \ =1

ln(C)-ln(1)=1, so then C=e^1=e

b) find P(X<2)

We can find this probability on this way using the density function:

P(X

c) find E(X) and Var(X)

We can find the expected value on this way:

E(X) =\int_{1}^e x \frac{1}{x} dx =x \Big|_1^e \ =e-1

In order to find the Var(X) we need to find the second moment given by:

E(X^2) =\int_{1}^e x^2 \frac{1}{x} dx =\frac{x^2}{2} \Big|_1^e \ =\frac{1}{2}(e^2 -1)

And now we can use the following definition:

Var(X)=E(X^2)-[E(X)]^2= \frac{1}{2}(e^2 -1) -(e-1)^2 = 0.242

5 0
4 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20°. What is the length of the arc? Either enter an exa
Semenov [28]

Answer:

\frac{\pi  }{3}

2 * \pi * 3  * \frac{20}{360}

120\pi/360 = \frac{\pi  }{3}

Step-by-step explanation:

5 0
3 years ago
Please help asap !!!!!!
KIM [24]

Answer:

w = 6

Step-by-step explanation:

Based on the midsegment theorem:

ST = 2(PR)

ST = w + 6

PR = w

Plug in the values into the equation

w + 6 = 2(w)

w + 6 = 2w

6 = 2w - w

6 = w

w = 6

5 0
3 years ago
Write the slope-intercept form of the equation of the line that is parallel to and passes through Point X. Show all work for ful
Lapatulllka [165]

Answer:

y=-1/3x+12

Step-by-step explanation:

To write a parallel first find the slope-intercept form of the first line- y=-1/3x+4

Then rewrite the equation with a y-intercept that will create a second line that passes through X on the graph.

(Although I believe this is right, please correct me if it is not. I, of course, could have made a mistake.)

6 0
4 years ago
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