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3 years ago

2 2/5 - 1 1/3 + 3 1/2

Mathematics

1 answer:

lakkis [162]3 years ago

8 0

Answer: 4 17/30

Step-by-step explanation:

2 2/5 - 1 1/3 + 3 1/2

(2 12/30 - 1 10/30) + 3 15/30

1 2/30 + 3 15/30 = 4 17/30

Have a nice day, and if you could be so nice as to give me a brainliest

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What is the answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Alecsey [184]

Answer:

$1559.40

Step-by-step explanation:

1. Find the perimeter of the garden

$14\frac{2}{3} + 14\frac{2}{3} + 10\frac{1}{3} + 10\frac{1}{3} = 50 yd$

2. Convert to feet

1 yd = 3ft

50 x 3 = 150

50 yd = 150 ft

3. Divide by 2.5 to find out how many sections are needed

150/2.5 = 60 sections

4. Multiply by 25.99

60 x 25.99 = 1559.4

It will cost $1559.40

3 0

3 years ago

A parallelogram is shown below:

Oliga [24]

Answer:

area of whole triangle is 3

area of triangle cut in half is 1.5

Step-by-step explanation:

Area: (.5)(8)(3/4)=3

Area of each triangle. It would be split down the middle. from a to c

3/2=1.5

3 0

3 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

4 years ago

A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d

Bas_tet [7]

Answer: $(4.0845,\ 6.5755)$

Step-by-step explanation:

As per given , we have

n = 11

$\overline{x}=5.33\\\\ s=1.33$

Since population standard deviation is missing, so we use t-test.

Critical t-value for 99% confidence :

$t_{\alpha/2,\ n-1}=3.106$ [using two-tailed t-value table]

Confidence interval :

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\= 5.33\pm (3.1060)\dfrac{1.33}{\sqrt{11}}\\\\\approx5.33\pm1.2455\\\\=(5.33-1.2455,\ 5.33+1.2455)\\\\=(4.0845,\ 6.5755)$