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2 years ago

Which of the following numbers can be expressed as a decimal that terminates? 3/2,2/3,3/4,5/7

Mathematics

1 answer:

wel2 years ago

6 0

Answer:

Step-by-step explanation:

An example of one fraction that does NOT terminate is 2/3.

2/3 = 0.666666666666666 .... That's the easy way to tackle the problem. Pick out the ones that don't terminate.

5/7 is the other one. It does not terminate either. It has 6 digits in a block that keeps on repeating itself forever.

5/7 = .571428 571428 which goes on forever.

So the two that do terminate are

3/2 which = 1.5

3/4 which = 0.75

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There is a 31/32 chance of having at least one boy

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3 years ago

How many paychecks do you get a year if you're paid semimonthly?

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2 years ago

How do i write the difference of a number x and 2 is 7 as an equation

HACTEHA [7]

You can quiet literally write the question as it is.

The difference of a number x and 2 is 7.

The difference of a number x and 2 can be written as x-2

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It is as simple as that!

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3 years ago

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1 year ago

Read 2 more answers

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

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3 years ago