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Readme [11.4K]
3 years ago
10

Discuss the nature of the roots x^2+6x=3

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0
x^2+6x=3\\
x^2+6x+9-9=3\\
(x+3)^2=12\\
x+3=\sqrt{12} \vee x+3=-\sqrt{12}\\
x=-3+\sqrt{12} \vee x=-3-\sqrt{12}\\
x=-3+2\sqrt{3} \vee x=-3-2\sqrt{3}\\
Lynna [10]3 years ago
5 0
x^{2} +6x=3
x^{2} +6x-3=0
using quadratic formula --> x= \frac{-6± \sqrt{6^{2}-4 *1*-3} }{2*1} 
x=-3+2 \sqrt{3} 
AND
x=-3-2 \sqrt{3}



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A/-8+15>23 isn't this weird to you guys too
yanalaym [24]
Let's solve your inequality step-by-step.
<span><span><span>
a − 8 </span>+ 15 </span>> <span>23

</span></span>Step 1: Simplify both sides of the inequality.
<span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>> 23
</span>
Step 2: Subtract 15 from both sides.
<span><span><span><span><span><span>
−1/</span>8</span>a </span>+ 15 </span>− 15 </span>> <span>23 − 15 
</span></span><span><span><span><span>
−1/</span>8</span>a </span>> 8 
</span>
Step 3: Multiply both sides by 8/(-1).
<span><span><span>
(<span>8/<span>−1</span></span>) </span>* <span>(<span><span><span>−1/</span>8</span>a</span>) </span></span>> <span><span>(<span>8/<span>−1</span></span>) </span>* <span>(8)
</span></span></span><span>
a < <span>−<span>64

Therefore, the answer is a < -64! I hope this helped! :)</span></span></span>
4 0
3 years ago
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
Tanya [424]

Answer:

  192 cm^3/min

Step-by-step explanation:

Differentiating the volume expression, we get ...

  dV/dt = 2xh(dx/dt) +x^2(dh/dt)

We are given that ...

  x = 4 cm, dx/dt = 2 cm/min, h = 15 cm, dh/dt = -3 cm/min

Putting these values into the formula for volume rate of change, we get ...

  dV/dt = 2(4 cm)(15 cm)(2 cm/min) +(4 cm)^2(-3 cm/min)

  = 240 cm^3/min -48 cm^3/min

  dV/dt = 192 cm^3/min

8 0
3 years ago
Home Videos Inc. surveys 450 households and finds that the mean amount spent for renting or buying videos is P135 a month and th
adell [148]

SOLUTION:

Case: Hypothesis testing

Step 1: Null and Alternative hypotheses

\begin{gathered} H_0:\mu=P127.50 \\ H_1:\mu\leq P127.50 \end{gathered}

Step 2: T-test analysis

\begin{gathered} t=\frac{\hat{x}-\mu}{\frac{s}{\sqrt{n}}} \\ t=\frac{135-127.5}{\frac{75.25}{\sqrt{450}}} \\ t=2.144 \end{gathered}

Step 3: t-test with the significance level

\begin{gathered} t_{\alpha}=? \\ \alpha=0.05 \\ From\text{ }tables \\ t_{0.05}=1.654 \end{gathered}

Step 4: Comparing

t>t_{\alpha}

So tail to reject the null hypothesis. There is enough evidence at a 0.05 level of significance to claim that the mean spent is greater than P127.50.

Final answer:

Yes, there is evidence sufficient to conclude that the mean amount spent is greater than P127.50 per month at a 0.05 level of significance.

6 0
1 year ago
How do you do this? It's geometry
antiseptic1488 [7]
45.

12/18 = 8/x <=> 2/3 = 8/x <=> x = (3*8)/2 = 12;
7 0
3 years ago
7/2x + 1/2x = 7 + 9/2x
lesya [120]

Answer: x=-14

Step-by-step explanation:

5 0
1 year ago
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