Answer:
Here's what I get
Explanation:
10. NH₃, ammonia
11. H₂CO₃, carbonic acid
12. CO₂, carbon dioxide
13. CaCO₃, calcium carbonate
14. PbCO₃ lead(II) carbonate
15. Co₃(PO₄)₂, cobalt(II) phosphate
16. As₂S₃, arsenic(III) sulfide.
Answer:
It increases when the temperature increases.
Explanation:
- According to Arrhenius relation: k = Ae(-Ea/RT).
- The rate constant of the reaction and also the rate of the reaction increases exponentially with increasing the temperature of the reaction.
- As the temperature increases, the no. of molecules that can posses the critical energy (activation energy) to initiate the chemical reaction and pass the energy barrier increases.
Answer:
44 grams of CO₂ will be formed.
Explanation:
The balanced reaction is:
C + O₂ → CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- C: 1 mole
- O₂: 1 mole
- CO₂: 1 mole
Being the molar mass of each compound:
- C: 12 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
By stoichiometry the following mass quantities participate in the reaction:
- C: 1 mole* 12 g/mole= 12 g
- O₂: 1 mole* 32 g/mole= 32 g
- CO₂: 1 mole* 44 g/mole= 44 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
If 12 grams of C react, by stoichiometry 32 grams of O₂ react. But you have 40 grams of O₂. Since more mass of O₂ is available than is necessary to react with 12 grams of C, carbon C is the limiting reagent.
Then by stoichiometry of the reaction, you can see that 12 grams of C form 44 grams of CO₂.
<u><em>44 grams of CO₂ will be formed.</em></u>
<u>Answer:</u> The molarity of sulfuric acid is 0.0946 M
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH
We are given:
Putting values in above equation, we get:
Hence, the molarity of sulfuric acid is 0.0946 M
