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fgiga [73]
3 years ago
9

C + O2 = CO2

Chemistry
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

44 grams of CO₂ will be formed.

Explanation:

The balanced reaction is:

C + O₂ → CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • C: 1 mole
  • O₂: 1 mole
  • CO₂: 1 mole

Being the molar mass of each compound:

  • C: 12 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole

By stoichiometry the following mass quantities participate in the reaction:

  • C: 1 mole* 12 g/mole= 12 g
  • O₂: 1 mole* 32 g/mole= 32 g
  • CO₂: 1 mole* 44 g/mole= 44 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

If 12 grams of C react, by stoichiometry 32 grams of O₂ react. But you have 40 grams of O₂. Since more mass of O₂ is available than is necessary to react with 12 grams of C, carbon C is the limiting reagent.

Then by stoichiometry of the reaction, you can see that 12 grams of C form 44 grams of CO₂.

<u><em>44 grams of CO₂ will be formed.</em></u>

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4 0
3 years ago
What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?
Inga [223]

Answer:

90.3 L

Explanation:

Given data:

Volume of water produced = 77.4 L

Volume of oxygen required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 6 moles of water = 6×22.414 = 134.5 L

Now we will compare:

                               H₂O           :              O₂    

                               134.5         :              156.9

                                 77.4         :             156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0
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100 POINTS!!! :0! What two things do all chemical reactions have in common (tick 2)? 1. They create new substances- the substanc
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Answer:

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Explanation:

7 0
3 years ago
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Complete combustion of 8.10 g of a hydrocarbon produced 25.9 g of CO2 and 9.27 g of H2O. What is the empirical formula for the h
balu736 [363]

CxHy     +  O2    -->    x CO2     +    y/2  H2O

 

Find the moles of CO2 :     18.9g  /  44 g/mol   =    .430 mol CO2   = .430 mol of C in compound

Find the moles of H2O:      5.79g / 18 g/mol     =     .322 mol H2O   = .166 mol of H in compound

 

Find the mass of C and H in the compound:

                             .430mol  x 12  =  5.16 g C

                              .166mol  x 1g   = .166g H   

 

When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.

Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).

In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).

8 0
3 years ago
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LiRa [457]

Answer:

1.52 g/mL

Explanation:

The formula for finding the density of an object is d = m/v, or density = mass divided by volume.

Therefore, we can input the two values and solve for d.

d = 220/145

d = 44/29

d ≈ 1.52 g/mL

8 0
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