Answer:
10.80 g of H2
Explanation:
As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen
The correct option would be that oxygen, nitrogen, and carbon dioxide cannot react with one another.
<h3>Why air components cannot react</h3>
The components of atmospheric air, nitrogen, oxygen, carbon dioxide, etc., cannot react with one another because there is not enough energy in the atmosphere to set the reaction rolling.
For a reaction to take place, there must be enough energy to break the bonds in each air component. This is why the air components will not spontaneously react with one another, except during special events such as lightning and thunder.
More on air components can be found here: brainly.com/question/17288850
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<u>Answer:</u> The value of 
for the given chemical equation is 0.0457.
<u>Explanation:</u>
Given values:
Initial moles of 
= 0.700 moles
Volume of conatiner = 3.50 L
The given chemical equation follows:
I: 0.700
C: -2x +2x x
E: 0.700-2x 2x x
Equilibrium moles of 
= x = 0.180 moles
Equilibrium moles of 
= 2x = 
Equilibrium moles of = 0.700 - 2x = 
Molarity is calculated by using the equation:
So,
![[SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M](https://tex.z-dn.net/?f=%5BSO_3%5D_%7Beq%7D%3D%5Cfrac%7B0.340%7D%7B3.50%7D%3D0.0971M)
![[SO_2]_{eq}=\frac{0.360}{3.50}=0.103M](https://tex.z-dn.net/?f=%5BSO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.360%7D%7B3.50%7D%3D0.103M)
![[O_2]_{eq}=\frac{0.180}{3.50}=0.0514M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D%5Cfrac%7B0.180%7D%7B3.50%7D%3D0.0514M)
The expression of for above equation follows:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Plugging values in above expression:
Hence, the value of for the given chemical equation is 0.0457.
