Answer:
52.0004 grams of mass of potassium superoxide is required
Explanation:
Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.
Pressure of the gas,P = 767 mm Hg = 0.9971 atm
Temperature of the gas,T = 22.0 °C = 295.15 K
Using an ideal gas equation to calculate the number of moles.
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
![n=\frac{0.9971 atm\times 8.90 L}{0.0821 atm L/mol K\times 295.15 K}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B0.9971%20atm%5Ctimes%208.90%20L%7D%7B0.0821%20atm%20L%2Fmol%20K%5Ctimes%20295.15%20K%7D)
n = 0.3662 mol
![4KO_2(s)+2CO_2(g)\rightarrow 2K_2CO_3(s)+3O_2(g)](https://tex.z-dn.net/?f=4KO_2%28s%29%2B2CO_2%28g%29%5Crightarrow%202K_2CO_3%28s%29%2B3O_2%28g%29)
According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.
Then 0.3662 mol of of carbon-dioxide will react with:
of potassium superoxide.
Mass of 0.7324 mol potassium superoxide:
0.7324 mol × 71 g/mol = 52.0004 g
52.0004 grams of mass of potassium superoxide is required.
A pure substance would be something containing only one type of molecule while a mixture consists of multiple pure substances.
Explanation:
your answer willing be 8.7
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