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3 years ago

Classify the following triangle check all that apply

Mathematics

1 answer:

saw5 [17]3 years ago

7 0

Answer:

c.Right

Step-by-step explanation:

because of the 90 degrees it shows that it is 90 degrees

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The quotient of 2 and t

tino4ka555 [31]

Answer: 2t/12

Step-by-step explanation:The quotient of is the result of dividing two terms

The first term is - Twice a number

4 0

3 years ago

An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, t

Alenkinab [10]

Answer:

The triangle's perimeter is 61.77 inches.

Step-by-step explanation:

Since an altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles, and as a result, the altitude cuts the base into two equal segments, and the length of the altitude is 26 inches, and the length of the base is 9 inches, to find the triangle's perimeter the following calculation must be performed:

Isosceles triangle = 2 equal sides

To obtain the value of the sides, the Pythagorean theorem must be applied on the right triangle formed with the altitude.

(9/2) ^ 2 + 26 ^ 2 = X ^ 2

4.5 ^ 2 + 26 ^ 2 = X ^ 2

20.25 + 676 = X ^ 2

√ (20.25 + 676) = X

√696.25 = X

26.38 = X

26.3865 x 2 + 9 = X

52.77 + 9 = X

61.77 = X

Therefore, the triangle's perimeter is 61.77 inches.

5 0

2 years ago

A sample of n = 4 scores is selected from a population with m = 40 with s = 8, and the sample mean is M = 43. What is the standa

vladimir2022 [97]

Standard error (SE)
$se= \frac{s}{ \sqrt{n} }$
Or

$se = \sqrt{ \frac{ {s}^{2} }{n} }$

Therefore, SE of the mean = (8)/(2) =4

5 0

3 years ago

1. Find the 90% Cl for the population mean if sample

Elden [556K]

Answer:

The answer is below

Step-by-step explanation:

mean (μ) = 12, SD(σ) = 2.3, sample size (n) = 65

Given that the confidence level (c) = 90% = 0.9

α = 1 - c = 0.1

α/2 = 0.05

The z score of α/2 is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.65

The margin of error (E) is given as:

$E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.65*\frac{2.3}{\sqrt{65} } =0.47$

The confidence interval = μ ± E = 12 ± 0.47 = (11.53, 12.47)

mean (μ) = 23, SD(σ) = 12, sample size (n) = 45

Given that the confidence level (c) = 88% = 0.88

α = 1 - c = 0.12

α/2 = 0.06

The z score of α/2 is the same as the z score of 0.44 (0.5 - 0.06) which is equal to 1.56

The margin of error (E) is given as:

$E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.56*\frac{12}{\sqrt{45} } =2.8$

The confidence interval = μ ± E = 23 ± 2.8 = (22.2, 25.8)

8 0

3 years ago

Ejercicio 34 - College Board

NISA [10]

360 es un globo, ⭕️, 180 es un

7 0

3 years ago