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3 years ago

How do we graph y+6=45(x+3)?

Mathematics

1 answer:

Bess [88]3 years ago

7 0

Answer:

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Which of the following describes the transformations of g (x) = negative (2) Superscript x + 4 Baseline minus 2 from the parent

o-na [289]

Answer: First option.

Step-by-step explanation:

Below are some transformations for a function $f(x)$ :

1. If $f(x)+k$ , the function is shifted "k" units up.

2 If $f(x)-k$ , the function is shifted "k" units down.

3. If $f(x-k)$ , the function is shifted "k" units right.

4. If $f(x+k)$ , the function is shifted "k" units left.

5. If $-f(x)$ , the function is reflected over the x-axis.

6. If $f(-x)$ , the function is reflected over the y-axis.

Then, given the parent function $f(x)$ :

$f(x)=2^x$

And knowing that the the other function is:

$g(x)=-2^{(x+4)}-2$

You can identify that the function $g(x)$ is obtained by:

- Shifting the function $f(x)$ 4 units left.

- Reflecting the function $f(x)$ 4 over the x-axis.

- Shifting the function $f(x)$ 2 units down.

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How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

elena-s [515]

Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

$\dfrac{2.5}{x+10}=0.1\implies25=x+10\implies x=15$

and so you would need to add 15 L of pure water to get the desired concentration of acid.

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4 years ago

How do we graph ​y+6=45(x+3)?

How do we graph y+6=45(x+3)?