ANSWER
The solution is where the two graphs intersect, which is

EXPLANATION
The given system of equations are

and

We need to graph the two equations.
Let us graph

first.
We need at least two points.
You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.
When




So this gives us the ordered pair,

When

we get,




This also gives the ordered pair

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.
For the second line

We again find the intercepts and plot them.
When



This gives the ordered pair

Also, when

then we have,



Then we again have the ordered pair,

We plot these two points on the same graph sheet to obtain the red graph above.
The intersection of the two lines is

You will get good grades so don't worry much.
8x-6y=-96 add to this -4 times the second equation...
-8x-12y=-48
___________
-18y=-144
y=8, this makes 8x-6y=-96 become:
8x-48=-96
8x=-48
x=-6
so the solution to the system of equations is the point:
(-6,8)
Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Answer:
56 cm^2
Step-by-step explanation:
Surface area is just finding the areas of each face in a figure. As we are given a net of a figure, it is much easier for us to calculate it.
Area of square base (side^2)
4^2 = 16 cm^2
Area of ONE triangular face (1/2 x b x h):
1/2 x 4 x 5 = 10 cm^2
Multiply that by 4 because we have 4 triangular faces: 10 cm^2 x 4 = 40 cm^2
ADD all the areas of triangles and square:
16 cm^2 + 40 cm^2 = 56 cm^2
HOPE THIS HELPS
Have a nice day!
The answer is c i’m pretty sure