Question

Find the x-intercepts (if any) for the graph of the quadratic function below. 6 y+4=(x-2)^2 a) (0, 0) and (-4, 0) b) (0, 0) and (4, 0) c) (0, 0) d) (-4, 0) and (4, 0) e) none

Answer 1

Answer:

The function has two x-intercepts at (0,0) and (4,0).

Step-by-step explanation:

Consider the provided function.

$y+4=(x-2)^2$

The x-intercepts are the point, where y is 0.

To find x-intercepts, substitute y = 0 in the provided equation and solve for x.

$0+4=(x-2)^2$

$4=(x-2)^2$

$\pm\sqrt{4}=x-2$

$\pm2=x-2$

$2=x-2$ or $-2=x-2$

$2+2=x$ or $-2+2=x$

$4=x$ or $0=x$

Therefore, the function has two x-intercepts at (0,0) and (4,0).