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hammer [34]
3 years ago
15

Find the x-intercepts (if any) for the graph of the quadratic function below. 6 y+4=(x-2)^2 a) (0, 0) and (-4, 0) b) (0, 0) and

(4, 0) c) (0, 0) d) (-4, 0) and (4, 0) e) none
Mathematics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

The function has two <em>x-</em>intercepts at (0,0) and (4,0).

Step-by-step explanation:

Consider the provided function.

y+4=(x-2)^2

The <em>x</em>-intercepts are the point, where <em>y</em> is 0.

To find <em>x-</em>intercepts, substitute <em>y</em> = 0 in the provided equation and solve for <em>x</em>.

0+4=(x-2)^2

4=(x-2)^2

\pm\sqrt{4}=x-2

\pm2=x-2

2=x-2 or -2=x-2

2+2=x or -2+2=x

4=x or 0=x

Therefore, the function has two <em>x-</em>intercepts at (0,0) and (4,0).

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Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k<br>2<br>-2<br>1/2<br>-1/2
Umnica [9.8K]

Answer:

Step-by-step explanation:

Using the graph we can notice something

let's take the abscissa  -2 and -4

  • the ordinate that goes with -2 using g is 0
  • the ordinate that goes with  -4 using f is 0

so we can say that :

f(-4)=g(-2)

wait we khow that g(x)=f(k*x)

so x= -2 then let's replace it in the expression : f(k*x)

we get f(-4)=g(-2)=f[k*(-2)]

let's solve the equation: -2k = -4

                                               k = -4/-2

                                                k=2

so finally we get k=2

let's check :

from the graph we get :

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  • g(-1)=2

we have (-1)*2 = -2

so it is true

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Alja [10]
Here!
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First you want to write the whole equation out. Make each perimeter equal to each other.
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