Answer:
B) Ill only
Step-by-step explanation:
This is because y = arcsin x can be re-written as sin y = x, We then differentiate sin y = x implicitly with respect to z to obtain
d(siny)/dz = dx/dz
(cosy)dy/dz = dx/dz
dy/dz = (1/cosy)dx/dz
Answer:
Answer in Explanation
Step-by-step explanation:
His reasoning is wrong. We can evaluate the validity of his reasoning by looking at the basics of what a polynomial is.
In the real sense of it, what makes a polynomial a polynomial is the power to which the variable is raised and not the integer attached to the variable.
In this case, we do not even have an integer attached.
What makes a polynomial a polynomial is that the variable is raised to an exponent or power which is a positive whole number ( integer)
In this case, while x^2 is a polynomial, x^-2 is not and also x^1/2 is not
Only x^2 is qualified as a polynomial because it is the only expression having its powers in positive integers
Hence; 0.5x^2 is a polynomial since it is raised to a positive whole number (integer)
The answer is: [B]: " 7 " .
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Note: Given: " x³ = 343 " ; Solve for "x" ;
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∛(343) = 7 .
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7³ = 7 × 7 × 7 = 343 .
7³ = 7 × 7 × 7 =
→ 7³ = 7 × 7 × 7 = 49 * 7 = 343 .
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Both expressions are graphs of a line. Plot the points and connect the dots. Graph will be two lines with open circle endpoints.
line from (-4,0) to (-3,1)
open circles at points
line from (6,11) to (3,5)
open circles at points