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mote1985 [20]
3 years ago
8

PLEASE HELP ASAP WITH#4

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0
Answer:
B.

Explanation:
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A professor drove from denver to boulder during rush hour at an average speed of 3030miles per hour, and then drove back the sam
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1hr = 60minutes
60min + 45 min = 105
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4 years ago
David made a scale drawing of a mural he is going to paint. He used a scale of 1 cm=4ft. If the actual mural will be 16 feet lon
Ne4ueva [31]

Answer:

The mural in David's drawing is <u>4 cm</u> long.

Step-by-step explanation:

Given:

David made a scale drawing of a mural he is going to paint.

He used a scale of 1 cm=4ft.

If the actual mural will be 16 feet long.

Now, to find how long is the mural in David's drawing.

Let the length of mural in David's drawing be x\ cm.

So, as given 1 cm = 4 ft.

1 cm is equivalent to 4 ft.

Thus, x\ cm is equivalent to 16 feet.

Now, to get the length of mural in David's drawing by using the cross multiplication method:

\frac{1}{4} =\frac{x}{16}

By cross multiplication:

16=4x

Dividing both sides by 4 we get:

4=x

x=4\ cm.

Therefore, the mural in David's drawing is 4 cm long.

8 0
3 years ago
Which of the following is not a triangle congruence theorem?<br><br> A) ASA<br> B) AAS<br> C) SSA
serg [7]
Don't listen to them asa is a very real thing! It's the angle side angle!! It would be C! Ssa! That doesn't exist!
3 0
3 years ago
Read 2 more answers
Francine has a picture whose length is 4/3 its width. She wants to enlarge the picture to have an area of 192 in2. What will the
nikklg [1K]
L=4W/3

A=LW, using L found above in this equation we have:

A=(4W)W/3

A=4W^2/3

3A=4W^2

3A/4=W^2

W=√(3A/4), we are told that A=192 in^2

W=√(3*192/4)

W=√144

W=12 in, since L=4W/3

L=4*12/3

L=16 in

So the length is 16 inches and the width is 12 inches.

6 0
3 years ago
Read 2 more answers
A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic
Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

\mathbf{Bars = 6}

\mathbf{Chocolate = 3}

\mathbf{Custard= 3}

The total number of donuts in the box is:

\mathbf{Total= 6 + 3 + 3}

\mathbf{Total= 12}

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}

So, we have:

\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}

Simplify

\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}

Multiply

\mathbf{Pr = \frac{9}{132}}

Divide

\mathbf{Pr = 0.068}

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068

Read more about probabilities at:

brainly.com/question/9000575

7 0
3 years ago
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