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mars1129 [50]
3 years ago
6

PLEASE IT IS EASY 6TH GRADE MATH PLEASE HELP! What is the answer?

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

A.12 hope you get a 100%

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Which statement is false?
Sidana [21]

Trigonometric functions which are related by having the same value at complementary angles are called cofunctions. Cofunctions of complementary angles are equal.

A. csc 20' = csc(90-70)=sec 70

B. cos 87' =  cos (90-3)=sin 3'

C. csc 40' =  csc(90-50) =sec50'  


D. tan 15' = tan(90-75)= cot 75'

Among all the option  c is not correct.

Option C is false.




8 0
4 years ago
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My opposite sides are parallel., and equal in length.All of my angles are equal in sides.
brilliants [131]

Hiya!

The answer is: quadrilateral

Every side of a quadrilateral are parralle and has the same length.

A quadrilateral is a 2-dimensional closed shape with four straight sides.

Have a nice day

4 0
4 years ago
What is the product of 1/3 and 4/7?
Travka [436]

Answer:

4/21

Step-by-step explanation:

Multiply 1 and 4. Then multiply 3 and 7. So 1x4=4, and 3x7=21. Therefore, the answer is 4/21. In multiplying fractions, you just multiply straight across (: (Hope this helps)

7 0
2 years ago
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Identify the domain of the function
sertanlavr [38]

The answer is C. is right

7 0
3 years ago
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Whats the roots of the following three problems:
klemol [59]

QUESTION 1

The given function is

f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}

We simplify to get;

f(x)=\frac{x-3}{x+2}

This function is equal to zero when x-3=0

\Rightarrow x=3

QUESTION 2

The given function is

f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}

f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}

We factor to get;

f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}

f(x)=\frac{5(x-1)}{(2x-3)}

This function equals zero when

5(x-1)=0

x=1

QUESTION 3

The given function is

f(x)=\frac{x^3-8}{x^2-6x+8}

We factor to get,

f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}

f(x)=\frac{x^2+2x+4}{x+4}

The function equals zero when x^2+2x+4=0

D=b^2-4ac

D=2^2-4(1)(4)

D=-12

Hence the equation has no real roots.

The complex roots are

x=-\sqrt{3}i-1 or x=-1+\sqrt{3}i

4 0
3 years ago
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