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mars1129 [50]
3 years ago
6

PLEASE IT IS EASY 6TH GRADE MATH PLEASE HELP! What is the answer?

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

A.12 hope you get a 100%

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Which choice is equivalent to the quotient shown here when X>0? Square Root 18x divided by square root 32
Marina86 [1]

Answer:

The answer is A

Step-by-step explanation:

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3 years ago
Geometry
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If the base is square, and the perimeter is 14.5, that means that each side of the base is 14.5/4=3.625. Since we now know the length and the width, as well as the height which is 16.8, we plug into the formula \frac{lwh}{3}. So, plug in the details \frac{3.625*3.625*16.8}{3} Your answer will be 73.6 cm^3

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Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =
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In Cartesian coordinates, the region is given by -3\le x\le3, -\sqrt{9-x^2}\le y\le\sqrt{9-x^2}, and -\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}. Converting to cylindrical coordinates, using

\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}

we get a Jacobian determinant of r, and the region is given in cylindrical coordinates by 0\le\theta\le2\pi, 0\le r\le3, and -\sqrt{16-r^2}\le z\le\sqrt{16-r^2}.

The volume is then

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3
6 0
3 years ago
Question 11 options:
9966 [12]

Answer:

x = 12

length = 4 cm

width = 20 cm

Step-by-step explanation:

a = lw

Plug in the givens

80 = (x - 8)(x + 8)

Multiply

80 = x^2 - 64

Add 64 to both sides

144 = x^2

Take the square root of both sides

x = ±12

(The negative root is extraneous since the dimensions can not be negative)

x = 12

length = x - 8 = 4 cm

width = x + 8 = 20 cm

7 0
3 years ago
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Yuliya22 [10]
D a rhombus because it dosnt always have congruent sides
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3 years ago
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