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2 years ago

Choose the correct expression for the nth term given the sequence. 5, 9, 13, 17, 21, . . .

Mathematics

2 answers:

Mamont248 [21]2 years ago

7 0

Answer:

i know you deleted my answer but...i really need pts im sorry

Step-by-step explanation:

i hope you forgive me pls dont delete my answer now

atroni [7]2 years ago

7 0

Answer:

4n+1

Step-by-step explanation:

Try with each expression to find the first one like. 5×1+1 is wrong because, you dont get 5 for the one, so its wrong. second one is 4×1-5 is wrong and you wont get the first answer.

the third one is the only one that actually gives the same numbers for the sequence given here.

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Write the trigonometry ratio for the triangle below.

Ludmilka [50]

Answer:

cos B = a/c

tan A = a/b

sin B = b/c.

Step-by-step explanation:

Sin = opposite / hypotenuse

cos = adjacent/ hypotenuse

tan = opposite/adjacent.

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

What is 13 28/30 simplest form

Naddik [55]

Answer:

13 14/15

Step-by-step explanation:

The numerator and denominator of 28/30 have a greatest common factor of 2. Dividing that from each of those numbers gives 14/15. This is the reduced fraction of the mixed number. The integer portion stays the same.

13 28/30 = 13 14/15

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2 years ago

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andrew11 [14]

Answer:

1a: 1,000,000

2a: 1

3a: 6

4a: 0

5a: 1

6a: 1

7a: 9

1b: 1

2b: 1

3b: 1

4b: 1

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6b:49

7b: 1

Step-by-step explanation:

6 0

1 year ago

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Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

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3 years ago

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