Question

2. Find the volume of the storage container shown. Round to the nearest tenth.

Answer 1

Step-by-step explanation:

2. The storage container is in the shape of a right circular cylinder with a diameter of 15 in and 10 in high. A right circular cylinder is considered a cylinder with circular bases with the axis of the cylinder being perpendicular (forms $90^{\circ}$) with the base.

The volume of a right circular cylinder is evaluated following the formula

                                                    $V \ = \ \pi r^{2}h$,

where $V$ denotes volume, $r$ is the radius of the circular base and $h$ is the height of the cylinder.

Plugging the given values into the formula and let $\pi \ = \ 3.1415$,

                                         $V \ = \ (3.1415)\left(\displaystyle\frac{15}{2}\right)^{2}(10) \\ \\ V \ = \ 1767.1 \ \ \text{in}^3 \ \ \ \ \ \ (\text{nearest tenth})$.

3. The ball is the shape of the sphere in which the volume is determined by the formula

                                                     $V \ = \ \displaystyle\frac{4}{3}\pi r ^{3}$.

Therefore,

                                             $V \ = \ \displaystyle\frac{4}{3}(3.1415)\left(\displaystyle\frac{38}{2}\right)^{3} \\ \\ V \ = \ 28730.1 \ \text{cm}^{3} \ \ \ \ \ (\text{nearest tenth})$