Half-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
Answer:
his displacement is 772.85 ft
Explanation:
Given;
initial velocity of his jump, u = 2 ft/s
final velocity of his jump, v = - 223 ft/s
time of motion, t = 7 seconds
acceleration due to gravity, g = 32.17 ft/s²
Let downward motion = positive direction
Let his displacement after 7s = Δh
Apply the following kinematic equation to determine his displacement.
Therefore, his displacement is 772.85 ft
Answer:
4,444,471 m/s
Explanation:
Use the momentum-impulse equation to find the change in velocity:
I = Δp = mΔv
We know the impulse given as well as the mass, we are trying to find the change in velocity hence the question how fast the car is going afterwards.
8.0*10^9 = 1800Δv
Simply divide 1800 to isolate Δv which gives:
4.4*10^6 = Δv
According to the calculator, the 4 is repetitive across all values so therefore it gives:
4,444,444 m/s = Δv
Now find the final/afterwards velocity:
vi + Δv = vf
27 + 4,444,444 = vf
4,444,471 = vf
The impulse given by the engine is out of this world quite literally.
Answer:
Explanation:
- The concept of gibb's free energy is applied in the problem. Mathematically from Gibb's free energy ; ΔG = ΔH - TΔS
- Entropy = ΔS = is the degree of disorderliness of the system.
- Since the enthalpy of vaporization is given ΔHvap = 38.0kJ/mol = 38000J/mol
- Also ΔSvap = 112.9J/mol.K
- Temperature of the experiment given = 75 degree celsius
calculate the boiling point of the solvent ; T = ΔHvap/ΔSvap
- T = 38000J/mol / 112.9J/mol.K
- = 335.57K , in celsius ; 335.57K - 273
the temperature calculated indicates that the solvent is not suitable for the experiment because its boiling point is lesser than the temperature at which the experiment want to be carried out.