Pre college need helppp

jok3333 [9.3K]

Answer:

3 (or x > 2)

Step-by-step explanation:

If your answer is only taking integers, then the first integer that would make this statement true would be 3. If it's for any numerical value, then the inequality would be true for any value above 2.

6 0

2 years ago

Read 2 more answers

The selling price of a refrigerator is $584. If the markup is 25% of the dealers cost, what is the dealer’s cost of the refriger

viva [34]

If you mark up 584 by 25%, you get 730. Therefore, the price of the refrigerator after the markup is $730.

5 0

4 years ago

Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a

Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .