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SpyIntel [72]
2 years ago
10

2.

Mathematics
1 answer:
trasher [3.6K]2 years ago
7 0

Answer:

how do you do this type of stuff I wanna learn so I can start to help other people

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HELP PLSSS THIS IS HARD SOMEONE
mariarad [96]

Answer:

The 4th option

Step-by-step explanation:

Mark me as brainliest please

5 0
3 years ago
I don’t know what she did wrong I can’t find anything
Dovator [93]

Answer:

she subtracted the 5 instead of adding it

Step-by-step explanation:

3 0
3 years ago
2350 million in standard form
topjm [15]

Answer:

in this problem we have

2,350 million

Remember that

1 million=1,000,000

so

2,350 million=2,350*1,000,000=2,350,000,000

convert to standard form

2,350,000,000=2.35*10^{9}

therefore

the answer is

2.35*10^{9}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The circumference of a circular garden is 138.16 feet. What is the radius of the garden? Use 3.14 for it and do not round your a
kobusy [5.1K]

Answer:

11 feet

Step-by-step explanation:

6 0
3 years ago
In one town, the number of burglaries in a week has a poisson distribution with a mean of 1.9. find the probability that in a ra
tester [92]

Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9

We have to find the probability that in a randomly selected week the number of burglaries is at least three.

P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........

= 1 - P(X < 3)

= 1 - [ P(X=2) + P(X=1) + P(X=0)]

The Poisson probability at X=k is given by

P(X=k) = \frac{e^{-mean} mean^{x}}{x!}

Using this formula probability of X=2,1,0 with mean = 1.9 is

P(X=2) = \frac{e^{-1.9} 1.9^{2}}{2!}

P(X=2) = \frac{0.1495 * 3.61}{2}

P(X=2) = 0.2698

P(X=1) = \frac{e^{-1.9} 1.9^{1}}{1!}

P(X=1) = \frac{0.1495 * 1.9}{1}

P(X=1) = 0.2841

P(X=0) = \frac{e^{-1.9} 1.9^{0}}{0!}

P(X=0) = \frac{0.1495 * 1}{1}

P(X=0) = 0.1495

The probability that at least three will become

P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]

= 1 - [0.2698 + 0.2841 + 0.1495]

= 1 - 0.7034

P(X ≥ 3 ) = 0.2966

The probability that in a randomly selected week the number of burglaries is at least three is 0.2966

5 0
3 years ago
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