The height of the object after 5.5 seconds is 394.875feet
<h3>Functions and values</h3>
Given the function that represents the height of the ball as shown:
In order to determine the height of the object after 5.5 seconds, we will substitute t = 5.5s into the formula to have;
Hence the height of the object after 5.5 seconds is 394.875feet
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Answer:
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Solving
2X + 3Y = 5.5
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Simplifying
2X + 3Y = 5.5
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<u>Solving for variable 'X'.
</u>
<u>
Move all terms containing X to the left, all other terms to the right.</u>
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Add -3y to each side of the equation.
2x + 3y + -3y = 5.5 + -3y
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Combine terms: 3y + -3y = 0.
2x + 0 = 5.5 + -3y
2x = 5.5 + -3y
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Divide each side by 2.
x = 2.75 + -1.5y
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Simplifying.
x = 2.75 + -1.5y
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It should be 146.667 feet per second
The perimeter of the parallelogram end is 2*(8 +5) = 26 cm. The product of that and the depth gives the lateral area.
The area of the parallelogram ends is 2*8*3, so the total area is
.. surface area = (26 cm)*(7 cm) +2*(8 cm)*(3 cm) = 230 cm^2
