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3 years ago

How many different ways can you add two odd numbers to get a sum of 20 and add examples

Mathematics

1 answer:

Sedaia [141]3 years ago

7 0

17+3
15+5
11+9
19+1

Hope this helps

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Help Please! Find The Circumference Of A Circle With D=22.1.

Pavlova-9 [17]

Answer:

72.25663

Step-by-step explanation:

C=2πr=2·π·11.5≈72.25663

8 0

2 years ago

Simplify 4(5+t)+2t<br> Please explain steps taken

Digiron [165]

Answer:

6t+20

Step-by-step explanation:

4(5+t)+2t =

= 20+4t+2t =

= 20+6t =

= 6t+20

6 0

2 years ago

Math quiz please help me out ASAP

Nastasia [14]

Answer:

The coordinates of point c: (7,5)

The coordinates of point D:(8,1)

3 0

2 years ago

Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

$1=-2x+3x^2+1$

$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

8 0

2 years ago

Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d

gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

Step-by-step explanation:

Evaluate:

$\dfrac{b-3a}{bc^{2}-d}$

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\$

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1$

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

6 0

3 years ago