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Vikentia [17]
3 years ago
13

HEY, I NEED HELP. QUICK. IM GETTING GROUNDED IF I DONT GET THIS DONE,,,, CHECKING IN ON YOU, HOW ARE YOU? HAVE YOU DRANK WATER?

REMEMBER, YOU ARE PERFECT. WHAT OTHERS SAY SHOULDNT MATTER. I KNOW WHAT PEOPLE SAY ABOUT YOU WILL HURT. BUT, THEIR OPINION IS TERRIBLE. YOU ARE VALID AND BEAUTIFUL. I LOVE YOU. HAVE A GOOD DAY. ❤️

Mathematics
2 answers:
aleksklad [387]3 years ago
6 0

Answer:

(2,-3)

Step-by-step explanation:

Aside from the solution below, you can also do this without needing a coordinate plane.

When you need to move right, you know that you will be only dealing with the x-axis, so the -3 will stay the same, untouched, (x, -3)

From now on, simply add +7 to -5 and you get (2,-3)

larisa [96]3 years ago
4 0

Answer:

0, -2 i think :p

Step-by-step explanation:

Because i say so

You might be interested in
Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point
Maksim231197 [3]

Answer: (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

or  (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

Taking square on both the sides , we get

(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0

Using quadratic formula : x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}

so, (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

since \sqrt{3}=1.732

so, (6+7(1.732),0)\text{ and }(6-7(1.732),0) are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0
3 years ago
Which of the following is an advantage of using systematic random sampling?
bekas [8.4K]

This is a question that asks about the advantages of a systematic random sampling. Thus, we first take a look at the types of sampling, and then we see the advantage of systematic random sampling.

Samples may be classified as:

Convenient: Sample drawn from a conveniently available pool.

Random: Basically, put all the options into a hat and drawn some of them.

Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.

Systematic:

One of the bigger advantages is that the systematic sampling eliminate clusters, which means that the last option is wrong.

Inadvertently missing patterns is a problem in systematic sampling, and not an advantage, thus the third option is also wrong.

It also does not reduce sampling variability, thus the first option is wrong.

From this, it can be concluded that the correct option is:

Systematic random sampling does not require a finite population size.

For another example of systematic random sampling, you can check brainly.com/question/21100042

8 0
2 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
It takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download
netineya [11]

Answer:

49

Step-by-step explanation:

35/5=7

7x7=49 seconds

6 0
3 years ago
Read 2 more answers
Question and answer in the picture
Luba_88 [7]

Answer:

m =3/4

Step-by-step explanation:

3x-4y = 12

We need to solve for y

Subtract 3x from each side

3x-3x-4y = -3x+12

-4y = -3x+12

Divide by -4

-4y/-4 = -3x/-4 + 12/-4

y = 3/4 x -3

This is in the form y = mx+b  where m is the slope and b is the y intercept

The slope is 3/4

3 0
2 years ago
Read 2 more answers
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