, Two triangles are similar. Triangle ABC has side lengths of AB = 10, BC = 6, CA = 7. Triangle XYZ has a side length of XY = 8. Find YZ.
Answer:
x = 1, y = -4
Step-by-step explanation:
7х + 2y = -1 ------ eq1
3х — 4y = 19 ------ eq2
multiply eq1 by 2
2 x (7х + 2y = -1)
14x + 4y = -2 -----eq3
by elimination, add equation 2 and 3
14x + 3x = 19-2
17x = 17 (divide both sides by 17)
x = 1 (answer)
substitute into eq1
7(1) + 2y = -1 (subtract 7 from both sides)
2y = -1 -7
2y = -8 (divide both sides by 2)
y = -8/2 = -4 (answer)
Answer:
-3 1/4
Step-by-step explanation:
12*3=36
3/12=1/4
If they are perpendicular, they form a right angle. For example, this is perpendicular:
I_
If likes are parallel, they run along each other, never meeting. For example, these two lines are parallel:
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Hope this helps!
Answer: 1 2 imm comingg for youuuuuuuuuuuuu
Step-by-step explanation: