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2 years ago

Any clue? Find the equation of the line shown.

Mathematics

1 answer:

icang [17]2 years ago

4 0

Answer:

Y= -X + 9 Can be found by trials

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If the temperature outside was 63 at 5:00 pm but it fell 21 degrees by 10:00 pm what is the temperature at 10:00 pm? Write the e

Naily [24]

It would be 42 degrese

r u using it 4 kahn XD

8 0

3 years ago

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Find the length of the bold arc. Round to the nearest tenth and use 3.14 or the pi button on your calculator for pi.

Elanso [62]

Answer:

8π yards

Step-by-step explanation:

A circle subtends a total angle of 360 ° from its center.The length of an arc is directly proportional to the angle it subtends from the circle's center. The arc's length can therefore be calculated as:

C=πd=2πr

Where C is circumference, d is diameter and r is radius. Given r as 16 yards then the arc length which is equivalent to circumference is given as

$C=\frac {90}{360}*2*\pi*16=8\pi$

4 0

3 years ago

What is 1/3+7/8 equal to?

stiks02 [169]

Answer:

1 5/24

Step-by-step explanation:

Common denominator is 24 so when you multiply 1/3 by 8 for the numerator and denominator it’s is equal to 8/24 and then you do the same for the other number except multiply by 3 which 21/24 then add together is 29/24 then simplified is 1 5/24

6 0

3 years ago

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A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible

steposvetlana [31]

Answer:

$AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

$AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}$

BA is:

$BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

8 0

3 years ago

Can someone please help me

Vlada [557]

>>>1/5 is the answer<<<

8 0

3 years ago