10 points

This two-way frequency table shows the results of a survey of users of the mass-transit system in a city. People were asked thei

lora16 [44]

Answer:

if Q={1,3,5,7,9}Express it in description methods

6 0

3 years ago

A baker makes apple tarts and apple pies each day. Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker

Lynna [10]

For this case, the first thing we must do is define variables.
We have then:
t: number of tarts
p: number of pies
We now write the system of equations:
Each tart, t, requires 1 apple, and each pie, p, requires 8 apples. The baker receives a shipment of 184 apples every day:
8p + t ≤ 184
the baker makes no more than 40 tarts per day:
t ≤ 40
Answer:
A system of inequalities that can be used to find the possible number of pies and tarts the baker can make is:
D. t ≤ 40
8p + t ≤ 184

5 0

3 years ago

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Rewrite the function by completing the square. h(x)= x^{2} +3 x -18 left parenthesis, x, right parenthesis, equals, x, squared,

ludmilkaskok [199]

Answer:

h(x) = (x +1.5)^2 -20.25

Step-by-step explanation:

We assume you want to rearrange h(x)= x^2 +3x -18.

Recognize the coefficient of x is 3. Add and subtract the square of half that. (3/2)^2 = 9/4 = 2.25

h(x) = (x^2 +3x +2.25) -18 -2.25

Now, write the expression in parentheses as a square, simplify the constant.

h(x) = (x +1.5)^2 -20.25 . . . . . . . . vertex form

4 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

170 percent converted to a fraction equals: ...?

Verdich [7]

There are several ways to do this by converting the percentage to a fraction by placing thee expression over 100100. Percentage means out of 100 and it will look like this 170/100.
Reduced the expression. 17/10
or in whole number it is 1 17/10

8 0

3 years ago

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