<img src="https://tex.z-dn.net/?f=15yx%5E%7B2%7D%20-34y-16" id="TexFormula1" title="15yx^{2} -34y-16" alt="15yx^{2} -34y-16" ali

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san4es73 [151]

1 year ago

gn="absmiddle" class="latex-formula">

Mathematics

1 answer:

svetoff [14.1K]1 year ago

7 0

Answer:

15yx^2-34y-16

Step-by-step explanation:

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A radio telescope has a parabolic surface, as shown below. If the telescope is 5 m deep and 40 m wide, how far is the focus from

Montano1993 [528]

Answer:

i think the answer is 8m

Step-by-step explanation:

4 0

3 years ago

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

2 years ago

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

Step-by-step explanation:

From the given right-angled triangle,

Base = p+1

Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

$=\frac{1}{2}\left(p+1\right)\left(2p-6\right)$

Factor 2p-6: 2(p-3)

$=\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}$

Divide the number: 2/2 = 1

$=\left(p+1\right)\left(p-3\right)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)$

$=pp-3p+1\cdot \:p-1\cdot \:3$

$=p^2-2p-3$

Therefore, we conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

3 0

2 years ago

Evaluate the expression: 0.5f - 2.3g where f = 12 and g = 2

m_a_m_a [10]

Answer:

1.4

Step-by-step explanation:

0.5f-2.3g where f=12 and g=2

substitute 12 in for f and 2 in for g and solve

0.5(12)-2.3(2)

6-4.6=1.4

4 0

2 years ago

Read 2 more answers

The area of a rectangular painting is 13.02 square feet. The width is 4.2 feet. What is the length?

Kay [80]

Answer:

3.1

Step-by-step explanation:

Since this is area and you are given the width must divide area by width ( A/W = L) 13.02 divided by 4.2 = 3.1. You can check this by doing 3.1 multiplied by 4.2. It should give you 13.02

3 0

3 years ago

Read 2 more answers