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san4es73 [151]
2 years ago
5

gn="absmiddle" class="latex-formula">
Mathematics
1 answer:
svetoff [14.1K]2 years ago
7 0

Answer:

15yx^2-34y-16

Step-by-step explanation:

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Please help with Part A and B. Thank you.
Jet001 [13]
Hello!

Part A:
The equation for a circle is (x - a)^2 + (y - b)^2 = r^2

We can say that the center of the earth is point (0, 0)

This gives us the equation

x^2 + y^2 = 3960^2

Square the number

x^2 + y^2 = 15681600

The answer is C
------------------------------------------------------------------------------------------------------
Part B

The answer is C) 69 miles

Hope this helps!
6 0
3 years ago
.<br> What is the surface area of this figure? Round your answer to the nearest tenth.
Harrizon [31]

Answer:

282.7 in²

Step-by-step explanation:

The formula of the surface area of cylinder is "2 times round areas + the height × circumference"

Round area = radius² × π

Circumference = diameter × π

In this case, the surface area is  2×5²×π + 4×10×π ≅ 282.743334

Nearest tenth is 282.7

4 0
3 years ago
The quadrilateral shown is a rectangle. What is m∠ZVY?<br> A) 39°<br> B) 59°<br> C) 61°<br> D) 119°
Sedbober [7]

Answer: hey bro i can solve this for you but you need to show the quadrilateral. without it i can't solve it.

Step-by-step explanation:

4 0
3 years ago
1: Look at the two inequalities above. What value of x makes both inequalities true?
Vesnalui [34]
Anything equal to or over 5
6 0
3 years ago
Read 2 more answers
Consider two markets: the market for cat food and the market for dog food. The initial equilibrium for both markets is the same,
umka21 [38]

Answer:

elasticity supply of dog food = 2.61

elasticity supply of cat food = 1.71

Step-by-step explanation:

The midpoint formula for elasticity is:

Elasticity = \frac{(Q2-Q1)/[(Q2+Q1)/2]}{(P2-P1)/[(P2+P1)/2]}

Point 1: Q = 39.0 and P = 5.50

Point 2: Q = 101.0 and P = 7.75

Elasticity\ supply\ of\ dog\ food = \frac{(101.0-39.0)/[101.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=2.61

Doing the same for the cat food:

Elasticity\ supply\ of\ cat\ food = \frac{(71.0-39.0)/[71.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=1.71

4 0
4 years ago
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