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3 years ago

Find the measure of the indicated angle to the nearest

Mathematics

1 answer:

fgiga [73]3 years ago

8 0

Answer:

? = 42°

Step-by-step explanation:

Let the missing angle be "x"

So:

Tan(x) = opposite/adjacent

Tan(x) = 33/37

x = Tan⁻¹(33/37)

x = 41.7,

if rounded to the nearest whole number:

x = 42

So ? = 42°

Hope this helps!

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In the triangle above, the cosine of a is 0.8.What is sine of b?

Natalka [10]

Answer:

sin b = 0.8

Step-by-step explanation:

Since a and b are complementary angles , then

sin b = cos a = 0.8

5 0

3 years ago

A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h\left( t \right)

iragen [17]

<u>Given</u>:

The height of the bird at time t is given by the function $h(t)=-4.9t^2+6t+50$

We need to determine the time it takes the worm to be eaten by the bird.

<u>Time taken:</u>

The time can be determined by substituting h(t) = 0 in the function.

Thus, we have;

$0=-4.9t^2+6t+50$

Switch sides, we get;

$-4.9t^2+6t+50=0$

Let us solve the equation using the quadratic formula.

Thus, we get;

$t=\frac{-6 \pm \sqrt{6^{2}-4(-4.9) 50}}{2(-4.9)}$

Simplifying, we get;

$t=\frac{-6 \pm \sqrt{36+980}}{-9.8}$

$t=\frac{-6 \pm \sqrt{1016}}{-9.8}$

$t=\frac{-6 \pm 31.87}{-9.8}$

The values of t are given by

$t=\frac{-6 + 31.87}{-9.8}$ and $t=\frac{-6 - 31.87}{-9.8}$

$t=\frac{25.87}{-9.8}$ and $t=\frac{-37.87}{-9.8}$

$t=-2.4$ and $t=3.9$

Since, the value of t cannot be negative, then $t=3.9$

Thus, the time taken by the bird to eat the worm is $t=3.9$ seconds.

Hence, Option B is the correct answer.

5 0

3 years ago

Please Help !!!

solong [7]

Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g

Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g

5 0

4 years ago

The game I want costs $60, but I only have $28 in my checking account. If I tried to buy this I would have _____.

Bogdan [553]

Answer:

$-32

Step-by-step explanation:

8 0

3 years ago

Which is the completely factored from of xy^3-x^3y

Oksanka [162]

Answer:

$xy(y+x)(y-x)$

Step-by-step explanation:

To factor the expression, remove the greatest common factor or GCF from each term. Both terms share in common xy. The expression becomes:

$xy^3-x^3y\\xy(y^2-x^2)$

What remains in the parenthesis is a different of perfect squares. Factor the difference of perfect squares into two binomials of the form (x+a)(x-a) where a is the square root of $(x^2-a^2)$ .

So the expression becomes:

$xy(y^2-x^2)\\xy(y+x)(y-x)$

7 0

3 years ago