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Sedbober [7]
3 years ago
15

HELP ASAP!!!!!

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0
Answer: Y= - 1/2x - 8
If you move y to one side by itself that’s what you’ll get and you can check this answer by multiplying each side by 2 and moving the x ti the left side and you’ll get your beginning equation

If it not right feel free to comment and tell me
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I'm confused on this problem 2/3x-1=5
sergey [27]

Answer:

x=9

Step-by-step explanation:

2/3x-1=5

Add 1 to each side

2/3x-1+1= 5+1

2/3x = 6

Multiply each side by 3/2

2/3x*3/2 = 6*3/2

x = 9

3 0
3 years ago
Read 2 more answers
Find the value of x or y so that the line through the points has the given slope
pishuonlain [190]
9)     -8/3 =  -8-0 /  x - 1 

so x = 4  

10)  -1/2 = 9-4 / -9-x
    -1/2 = 5 / -9-x
     9+x =  10
x = 10-9 = 1


6 0
3 years ago
A varies directly as b, and a =4 when b=24 write an equation that relates a and b
uysha [10]
Y=kx
K=y/x

SO:
A=kb
K=a/b
5 0
3 years ago
Two people decided to race. One of the cars is 10 meters north of the start line 5 seconds into the race. After 15 seconds, the
sleet_krkn [62]

Answer:

The average velocity of the car is 1.5 m/s

Step-by-step explanation:

The given parameters are;

The displacement of one of the cars north of the start after 5 seconds = 10 meters

The displacement of the car north of the start after 15 seconds = 25 meters

The average velocity of the cars \overline v is given as follows;

\overline v = \dfrac{\Delta x}{\Delta t}

Where;

Δx = The change in the displacement of the car = 25 m - 10 m = 15 m

Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s

By substituting the known values of Δx and Δt in the equation for the average velocity of the car, \overline v, we have;

\overline v = \dfrac{15 \ m}{10 \ s} = 1.5 \ m/s

∴ The average velocity of the car, \overline v = 1.5 m/s

4 0
3 years ago
If m2=115,what is m1
erastovalidia [21]

Answer: the correct answer is 65

8 0
3 years ago
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