Answer:
Step-by-step explanation:
So, we have-
(6 x .1) + (3 x .01) + (2 x .001)
So, we will solve inside of the parenthesis first.
6 x .1 = <u>.6</u>
So, we got that settled next-
3 x .01 = <u>.03</u>
We got that settled last-
2 x .001 = <u>.002</u>
Lastly, we add them all.
.6 + .03 + .002 = .632
Now we compare.
.632 > .629
So, there is your answer!
Hope this helps!
Answer:
The probability is 0.33696
Step-by-step explanation:
The probability that the outcome will be heads x times is calculated using the following equation:
![P(x) = nCx*p^{x} *(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28x%29%20%3D%20nCx%2Ap%5E%7Bx%7D%20%2A%281-p%29%5E%7Bn-x%7D)
nCx is calculated as:
![nCx=\frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=nCx%3D%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
This apply for variables that follows a binomial distribution. In which we have n independent and identical events with two possibles results: success and fail with a probability p and 1-p respectively.
So, In this case, n is equal to 5, and p is equal to 0.6 because we are going to call success the event in which the outcome of the coin is head.
Then, the probability that the outcome will be heads at least 4 times is calculated as:
P = P(4) + P(5)
Where P(4) is:
![P(4) = 5C4*0.6^{4} *(1-0.6)^{5-4}](https://tex.z-dn.net/?f=P%284%29%20%3D%205C4%2A0.6%5E%7B4%7D%20%2A%281-0.6%29%5E%7B5-4%7D)
P(4)=0.2592
And P(5) is:
![P(5) = 5C5*0.6^{5} *(1-0.6)^{5-5}](https://tex.z-dn.net/?f=P%285%29%20%3D%205C5%2A0.6%5E%7B5%7D%20%2A%281-0.6%29%5E%7B5-5%7D)
P(4)=0.07776
Finally, the probability is:
P = 0.2592 + 0.07776
P = 0.33696
Answer:
2. unabated
3. vindication
4. commence
5. prudence
6. denunciation
Step-by-step explanation:
Answer: No the students work is not correct. Because you are using distribution. Which means that 3 has to multiply the y2 and 2 not just the y2! And after you distribute it you need to simplify!
Step-by-step explanation: