Which approach to bandwidth usage consumes all of the available frequencies on a medium to transmit data

How to find out what version of windows i have?

Sholpan [36]

Look in for setting under system settings, that should show what software and firmware version you are on.

3 0

4 years ago

Using data from a tal distribution database, define a view named toplevelcust. it consists of the number, name, address, balance

valentina_108 [34]

A) CREATE TABLE toplevelcust (number INTEGER PRIMARY KEY, <span> name TEXT, address TEXT, balance DOUBLE, credit DOUBLE</span>);

b) select number, name, credit - balance from toplevelcust

c) This I cannot answer

7 0

3 years ago

Read 2 more answers

2. Suppose a computer using direct mapped cache has 220 words of main memory and a cache of 32 blocks, where each cache block co

Advocard [28]

Answer:

(a) The block size = 16 words (b) the format for the sizes of the tag, block, and word fields are stated below:

Tag Block Offset

11 bits 5 bits 4 bits

(c)The memory address 0DB63 will map to 22nd block and 3 byte of a block. (d) The main advantage of the cache is, when the cache block is made larger or bigger then, there are fewer misses. this occur when the data in the block is used.

One of the disadvantage is that if the data is not used before the cache block is removed from the cache, then it is no longer useful. here there is also a larger miss penalty.

Explanation:

Solution

(a)The Cache of 32 blocks and the memory is word addressable

The main memory size is not stated, so let's consider it as 2^20

The main memory size = 2^20

The block size = 16 words

The Number of blocks = main memory size/ block size = 2^20/16. = 2^16= 64 K words.

(b) The Main memory is 2^20, which says it is 1 M words size and it requires 20 bits

Now,

From which 32 cache block requires 2^5, 5 bits and block size means offset requires 2^4, 4 bits

Thus, the sizes of the tag, block, and word fields are stated below:

Tag Block Offset

11 bits 5 bits 4 bits

(c)The hexadecimal address is 0DB63 , its binary equivalent is

0000 1101 1011 0110 0011

The tag = ( first 11 bits) = 0000 1101 101

block = ( next 5 bits ) = 1 0110

offset = ( next 4 bits ) = 0011

Therefore, the memory address 0DB63 will map to 22nd block and 3 byte of a block.

(d) The main advantage of the cache is that, when the cache block is made larger or bigger then, there are fewer misses. this occur when the data in the block is used.

One of the disadvantage is that if the data is not used before the cache block is removed from the cache, then it is no longer useful. here there is also a larger miss penalty.

3 0

3 years ago

Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Rom

Studentka2010 [4]

Answer:

// program in C++.

// headers

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// Variable

int num;

cout << "Enter a number between 1 and 10: ";

// read input

cin >> num;

// validate input number

while(num<1||num>10)

{

// if input is wrong then print error message

cout<<"Wrong input!!Enter again:";

// read again

cin>>num;

}

// print output

cout << "The Roman numeral for "<<num<<" is:";

// switch

switch (num)

{

case 1:

// if input is 1

cout<<"I"<<endl;

// exit the switch

break;

case 2:

// if input is 2

cout<<"II"<<endl;

// exit the switch

break;

case 3:

// if input is 3

cout<<"III"<<endl;

// exit the switch

break;

case 4:

// if input is 4

cout<<"IV"<<endl;

// exit the switch

break;

case 5:

// if input is 5

cout<<"V"<<endl;

// exit the switch

break;

case 6:

// if input is 6

cout<<"VI"<<endl;

// exit the switch

break;

case 7:

// if input is 7

cout<<"VII"<<endl;

// exit the switch

break;

case 8:

// if input is 8

cout<<"VIII"<<endl;

// exit the switch

break;

case 9:

// if input is 9

cout<<"IX"<<endl;

// exit the switch

break;

case 10:

// if input is 10

cout<<"X"<<endl;

// exit the switch

break;

// default

default:

break;

}

return 0;

}

Explanation:

Read a number from usr and assign it to variable "num". If the input number is less than 1 or greater than 10 then ask again to enter a number until user enter a number between 1-10 only.Then with the help of switch() function print the equivalent Roman number.

Output:

Enter a number between 1 and 10: -5

Wrong input!!Enter again:12

Wrong input!!Enter again:6

The Roman numeral for 6 is:VI

7 0

3 years ago

What tool is provided in Windows to facilitate sharing data objects between applications and computers?

Anton [14]

Answer:

Component services

Explanation:

In Windows, components services are integrated into the Administrative Tools and are used to configure certain COM (Component Object Model) components and applications. They are also used to ;

i. assign roles to users and groups.

ii. facilitate data sharing between applications and computers by processes such as pooling, pausing, resuming and recycling applications.

7 0

3 years ago