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2 years ago

The Kicking Cacti and the Sprinting Stingrays met in their town's annual kickball

1 answer:

4 0

Using proportions, it is found that each of the pitchers for the Stingrays pitched for $\mathbf{\frac{11}{3} = 3\frac{2}{3}}$ innings.

This question is solved by proportions, using a rule of three.

In total, the Stingrays pitched 11 innings, with 3 pitchers. Each pitcher pitched the same amount of innings, hence, 1 pitcher pitched x innings.

The rule of three is:

3 pitchers - 11 innings

1 pitcher - x innings

Applying cross multiplication:

$3x = 11$

$x = \frac{11}{3}$

11 divided by 3 has result 3 with remainder 2, hence, also considering the answer as a mixed number:

Each of the pitchers for the Stingrays pitched for $\mathbf{\frac{11}{3} = 3\frac{2}{3}}$ innings.

You can learn more about proportions at brainly.com/question/24372153

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A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan

svlad2 [7]

Answer:

$t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$

Step-by-step explanation:

We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.

7 0

3 years ago

Determine

mihalych1998 [28]

Answer:

$=4.+2.$

Step-by-step explanation:

Linear Combination Of Vectors

One vector $\vec b$ is a linear combination of $\vec a_1$ and $\vec a_2$ if there are two scalars $x_1, x_2$ such as

$\vec b=x_1\vec a_1+x_2\vec a_2$

In our case, all the vectors are given in $R^3$ but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

$\vec a_1=,\ \vec a2=,\ \vec b=$

We set the equation

$=x_1.+x_2.$

Multiplying both scalars by the vectors

$=+$

Equating each coordinate, we get

$4x_1-4x_2=8$

$5x_1+3x_2=26$

$-4x_1+3x_2=-10$

Adding the first and the third equations:

$-x_2=-2$

$x_2=2$

Replacing in the first equation

$4x_1-4(2)=8$

$4x_1=8+8$

$x_1=4$

We must test if those values make the second equation become an identity

$5(4)+3(2)=20+6=26$

The second equation complies with the values of $x_1$ and $x_2$ , so the solution is

$=4.+2.$

8 0

3 years ago

I'm in need of help. The file should be attached to this. Thanks for your help!

Amanda [17]

company a: 2mins

company b: 7mins

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6 0

3 years ago

Suppose you accumulated $500,000, perhaps from many years of saving. You put the money in a savings plan earning 6% compounded m

nata0808 [166]

The monthly interest rate is 6%/12 = 0.5%. The interest earned each month is
0.005*$500,000 = $2500

You can withdraw $2500 each month without disturbing the principal amount.

3 0

3 years ago

I Need Help With This One

Arisa [49]

Answer:

x = -6 x= -3

Step-by-step explanation:

f(x) = x^2+9x+18

Set equal to 0 to find the zeros

0 = x^2+9x+18

Factor, what numbers multiply to 18 and add to 9

6*3 =18

6+3=9

0= (x+6) (x+3)

Using the zero product property

x+6 =0 x+3 =0

x = -6 x= -3

7 0

3 years ago