Good evening.
We want:
The function is <em>not continuous</em> in 3, and f(3) = 7, but, as we approach to 3 from right, we are always in
f(x) = 3.
We can approach to indefinitely close to x = 3 from right, and the function will be always in 3. Therefore, we conclude that:
In order to put these numbers on a number line, you need to draw a number line and then count backwards to find your answer.
<h3>How do you put the equation on the number line?</h3>
The first thing to do is to draw a number line from -9 to 3.
Then look at the equation which is:
-8 - -9 = 1
-8 + 9 = 1
The two negatives become a positive.
Because the sign is positive, you will count backwards on the number line a total of 9 places. This will then take you to 1.
Find out more on number lines at brainly.com/question/24644930
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(if the last five is an exponent, here is the answer)
5 • 10^5
first work on the exponent
5 • 100,000
multiply
500,000
The transformation is ISOMETRY.
In mathematics, an isometry<span> (or congruence, or congruent transformation) is a distance-preserving transformation between metric spaces, usually assumed to be bijective. A composition of two opposite </span>isometries<span> is a direct </span>isometry<span>. A reflection in a line is an opposite </span>isometry<span>, like R </span>1<span> or R </span>2<span> on the image.</span>
