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Burka [1]
3 years ago
7

PLZZ HELP BASIC ALGEBRA Solve the equation 8+2z=3(2-z)

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

z = -\frac{2}{5} or - 0.4

Step-by-step explanation:

8+2z = 6 - 3z

2z = 6 - 8 - 3z

2z + 3z = - 2

5z = -2

z = -\frac{2}{5} or - 0.4

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4. need help with this question - give the brainliest answer whoever answer it fully
kondaur [170]
1. Monday diagram probability of no rain will be 0.45
2. Tuesday diagram probability of no rain will be 0.75 and rains will be 0.25
7 0
2 years ago
Jason jumped of a cliff into the ocean . His height as a function off time could be models as h(t)=16tsquared + 16t + 480 where
Karo-lina-s [1.5K]

I see that you are in high school, and I'm hoping that you've been introduced
to differential calculus, because I don't know how to answer this question without
using it.

We're told that Jason's height above the water is  <em>H(t) = -16t² + 16t + 480 .</em>
We can observe many things from this equation:
-- Up is the positive direction; down is the negative direction.
-- The acceleration of gravity is 32 ft/sec² .
-- Jason jumps upward from the cliff, at 16 ft/sec .
-- The cliff is 480-ft above the water.
(This tells us why the question is only concerned with his maximum height,
and then it ends ... 480-ft is one serious cliff, and what happens after the
peak of his arc is too gruesome to contemplate.)

In any case, his vertical velocity is the first derivative, with respect to time,
of his height above the water.

         V = -32 t + 16

At the peak of his arc, where gravity takes over, his velocity changes from
upward to downward, and it's momentarily zero.

                                           0 = -32t + 16

Add  32t  to each side:    32t = 16

Divide each side by  32:    <em>  t = 1/2 second</em>

His height at that instant is     H(0.5) = -16(0.5)² + 16(0.5) + 480 =

                                           <em>4-ft above the cliff,  484-ft above the water</em>,

and then he begins falling from that altitude.

The duration of his dive is      484 = 16 t²
                                                   t = √(484/16) = <em>5.5 seconds</em>

and he hits the water at      V = a t = (32) x (5.5) = 176 ft/sec = <em>exactly 120 mph </em>

Jason was good man ... a good student, and always kind to everyone he met.
He will certainly be missed.


5 0
3 years ago
The ages of members of an online gaming group are normally distributed with a mean of 23 years and a standard deviation of 4 yea
Lelechka [254]
To get the number of members between 15 years and 30 years we proceed as follows:
z=(x-μ)/σ
where:
mean,μ=23
standard deviation, σ=4 years
thus
P(15<x<31)
when x=15
P(x<15)
z=(15-23)/4
z=-2
thus
P(x<15)=P(z<-2)=0.0228

when x=31
z=(31-23)/4
z=2
thus
P(x<31)=P(z<2)=0.9772
Hence:
P(15<x<31)=0.9544
hence the number of members between that age was:
0.9544×300
=286.32 people
~285 People
Answer: 285 people

5 0
3 years ago
Find the perimeter and area of the following
elena55 [62]

16. PM = 26x + 8x^2y

A = 52x^3y

17. Area = 33a^5b

3 0
2 years ago
Evaluate p\4 when p=12
NikAS [45]
P/4 p=12 just plug in 12 for p
12/4 4*3=12 12/4=3
Hope this helps have a nice nite
7 0
3 years ago
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