Please help me (both images are supposed to be together.)
1 answer:
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Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= [∑X₁² - (( ∑X₁)²/n₁)]=
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
Answer: D) 52%
Step-by-step explanation:
G = gymnastics
B = baseball
S = soccer
G = 28%
BA = 29%
S = 19%
G and BA = 14%
BA and S = 12%
G and S = 10%
GBS = 8%
So, as we can see at the Venn diagram attached (consider every number in %)
GBS = 8
A = G and S - GBS = 10 - 8 = 2
B = G and BA - GBS = 14 - 8 = 6
C = BA and S - GBS = 12 - 8 = 4
Only G = G - A - B - GBS = 28 - 2 - 6 - 8 = 12
Only BA = BA - B - C - GBS = 29 - 6 - 4 - 8 = 11
Only S = S - A - C - GBS = 19 - 2 - 4 - 8 = 5
So, 2+6+4+12+11+5+8 = 48
100 - 48 = 52%
