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Rasek [7]
3 years ago
13

A ladder leaning against a wall forms a triangle and exterior angles with the wall and the ground. What are the measures of the

two exterior angles? (These are (1) the ladder to the ground and (2) the ladder to the side of the house.) Justify your answer.

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0
11x° is interior angle of ladder to the ground
and 7X° is interior angle of ladder to the wall

exterior angle of a ladder to wall is 180-7x
and exterior angle of a ladder to ground is 180-11x
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kifflom [539]

Step-by-step explanation:

(X1,Y1) = (-2,2)

(X2,Y2) = (0,1)

• Find slope.

m = (Y2 - Y1)/(X2 - X1)

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Right answer gets brainlyest
DiKsa [7]

Answer:

right answer

Step-by-step explanation:

B)

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Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
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8 0
3 years ago
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lesantik [10]

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What is the slope of the line
kolbaska11 [484]

Answer:

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