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2 years ago

10

a waiter earns $13.65 per hour and must give 10% of his tips to the kitchen staff. he worked 8 hours last Friday and made $213 i

n tips. What was his gross pay for the shift?

1 answer:

Nata [24]2 years ago

4 0

Answer:

10% of 213 is 21.30

213-21.3= 191.7

gross income: 191.7

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A phone sells for $250. It is now on sale for 1··5off the original price. April has a coupon for an extra 10% off the sale price

anastassius [24]

It's on a sale for 1 fifth of the original price?

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2 years ago

A container ship left port last week caring some good weighing a total of 125,890 tons today I stopped in another port to unload

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

You need to be specific. Did the weight decrease by 60 tons or 60 pounds? I assume tons, but in math, you can't assume.

This problem seems overly simple, so I am wondering if some information is missing. With the given information and assuming the decrease was in fact 60 tons, you would have:

125,890 - 60 = 125,830 tons

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3 years ago

The function f(x) = 40sin(0.1x + 12) + 50 represents the number of items, f(x), made in a factory each day for x days. The data

Sladkaya [172]

Answer:

its 11 and 31

Step-by-step explanation:

got it right on test

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3 years ago

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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont

anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

$P=\int^{T}_{0}f(t)e^{-rt}dt$

where:

T is the period in years (T = 10 years)
r is the annual interest rate (r=0.08)

So we have:

$P=\int^{T}_{0}(0.01t+100)e^{-rt}dt$

Now we just need to solve this integral.

$P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt$

$P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}$

$P=0.30+688.34=688.64 $$

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

$A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt$

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

$A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P$

$A=e^{0.08\cdot 10}688.64=1532.60 $$

The accumulated amount is 1532.60 $

Have a nice day!

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2 years ago

Identify the scale factor

olga_2 [115]

Answer:

2

Step-by-step explanation:

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2 years ago

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