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3 years ago

15

150 students of a hostel have food enough for 45 days 25 students leave the hostel after 10 days how much longer will the remain

ing food last

1 answer:

Andru [333]3 years ago

5 0

Answer:

The answer will be 9 food last

You might be interested in

Pete is a politician. He claims that 32% of the households in his district have total household incomes below the poverty level.

victus00 [196]

Answer:

$z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145$

For a bilateral test the p value would be:

$p_v =2*P(z>2.145)=0.0320$

Step-by-step explanation:

Information given

n=225 represent the sample selected

X=87 represent the households with incomes below the poverty level

$\hat p=\frac{87}{225}=0.3867$ estimated proportion of households with incomes below the poverty level

$p_o=0.32$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if the true proportion is equal to 0.32 or not.:

Null hypothesis: $p=0.32$

Alternative hypothesis: $p \neq 0.32$

The statistic is given bY:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.3867 -0.32}{\sqrt{\frac{0.32(1-0.32)}{225}}}=2.145$

For a bilateral test the p value would be:

$p_v =2*P(z>2.145)=0.0320$

4 0

4 years ago

Random/probability sampling is when everyone in the group you are studying has an equal chance of participating.

zaharov [31]

Probability sampling<span> is when everyone in the group you are studying has an equal chance of participating.</span>

7 0

3 years ago

What is the answer to 2+b=7

Natasha_Volkova [10]

Answer:

b=5

Step-by-step explanation:

2+b=7

Subtract 2 from each side

2+b-2=7-2

b= 5

7 0

3 years ago

a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the

alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

= (150)²

= 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

= 150 + (2×5)

= 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

= (160)²

= 25600 m²

Area of road = Area of the park with road - Area of the park

= 25600 - 22500

= 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

= 775000 rupees

6 0

2 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

3 years ago