64 = 2 ^6
16 = 2^4 =
2^ 6*(2x+4) = 2^4 * 5x
6(2x+4) = 20x
10/3 x = 2x +4
4/3 x = 4
x = 3
you can also use logarithms like so
(2x+4)ln64 = 5x ln16
ln64/ln16 = 3/2
3/2 * 2x + 3/2 * 4 = 5x
3x + 6 = 5x
2x = 6
x = 3
Answer:
i think he reads like 30 pages per hour
Step-by-step explanation:
Answer:
x = -1
x = -5
Step-by-step explanation:
y= (x+3)^2 - 4
(x + 3)^2 = x^2+6x+9
y = x^2 + 6x + 9 - 4
y = x^2 + 6x + 5
x^2 + 6x = -5
x^2 + 6x + 9 = -5+9 (6/2=3, 3^2 = 9) (add 9 to both sides)
(x + 3)^2 = 4
x + 3 = sqrt 4
x + 3 = +- 2
x + 3= 2. x = 2-3. x = -1
x + 3 = -2. x = -3-2. x = -5
9514 1404 393
Answer:
3
Step-by-step explanation:
Assuming your two equations are ...
You want to find the multiplier k such that ...
6 + (-2)k = 0 . . . . total x-coefficient after the equations are combined
Dividing by 2 gives ...
3 - k = 0
3 = k . . . . . . add k
The multiplier needed is 3.
There is only one 5/6 in one
