3.295 kg x 1000g / kg x 1 ounce / 28.3g
116.43 ounces
Answer:

Step-by-step explanation:
In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).
The formula we will use for this problem is the following:

where:


a=0

so the volume becomes:

This can be simplified to:

and the integral can be rewritten like this:

which is a standard integral so we solve it to:
![V=9\pi[tan y]\limits^\frac{\pi}{3}_0](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20y%5D%5Climits%5E%5Cfrac%7B%5Cpi%7D%7B3%7D_0)
so we get:
![V=9\pi[tan \frac{\pi}{3} - tan 0]](https://tex.z-dn.net/?f=V%3D9%5Cpi%5Btan%20%5Cfrac%7B%5Cpi%7D%7B3%7D%20-%20tan%200%5D)
which yields:
]
Answer:
160,000 tins
Step-by-step explanation:
To find the number of tins, divide the fill rate by the volume per tin.
__
(2·(1000 L)/min)×(60 min)/(1 h)/(0.75 L/tin) = 160,000 tin/h
160,000 tins of paint can be filled in 1 hour.
_____
<em>Additional comment</em>
That's one tin every 22.5 milliseconds. It would be a feat of engineering to move that volume without splashing.
There are 60 minutes per hour. There are 1000 liters per cubic meter.
Answer:
2x2x3x3
Step-by-step explanation:
36
2 18
2 9
3 3