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sattari [20]
2 years ago
5

PLEASE HELP I FORGOT EVERYTHING

Mathematics
2 answers:
Phantasy [73]2 years ago
6 0

\huge{\textbf{\textsf{{\color{navy}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

\frac{2}{x}  =  \frac{5}{3}

By doing cross multiplication.

6 = 5x \\  x = \frac{6}{5}  \\ x = 1.2

  • Thanks
  • Hope it helps
  • Pls mark as brainliest
Mashcka [7]2 years ago
3 0

Answer:

the answer you are looking for is A ,1.2

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If the function f(x) = (2x - 3) is transformed to g(x) = (-2x - 3), which type of transformation occurred?
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4 0
2 years ago
1.<br> A. 3.75<br> B. 1.5<br> C. 3<br> D. 4.5<br><br> 2.<br> A. 30<br> B. 16<br> C. 8<br> D. 15
Gnom [1K]

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4 0
3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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