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2 years ago

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If f(x) = 4x2 + 2x + 7, find the value of f(-5). = A. -103 B. -83 C. 97 D. 117

1 answer:

Aloiza [94]2 years ago

7 0

D. 117
4(5)^2+2(5)+7
4(25)+(10)+7
100+10+7= 117

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A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

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2 years ago

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Answer:

163%

Step-by-step explanation:

Find in-between 25 and 300, which is 162.5 ,round to the nearest percentage being 163%. Hence your answer

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2 years ago

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115:55 bc if you divide them both you fat the same answer which is 2

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2 years ago

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Find the sum using fraction bars or a paper and pencil. Write your answer in simplest form.

vlabodo [156]

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3 years ago

In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo

Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

$P(B) = 0.6$

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

$P(A/B) = x$

P(A) is the probability that the participant dies:

$P(A) = P_{1} + P_{2} + P_{3}$

$P_{1}$ is the probability that a heavy smoker is selected and that he dies. So:

$P_{1} = 0.15*5x = 0.75x$

$P_{2}$ is the probability that a light smoker is selected and that he dies. So:

$P_{2} = 0.25*3x = 0.75x$

$P_{3}$ is the probability that a non-smoker is selected and that he dies. So:

$P_{3} = 0.60*x = 0.60x$

The probability that a participant dies is:

$P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x$

The probability of the participant being a non-smoker, given that he died, is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857$

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

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3 years ago