3 years ago

Find the difference. 4ab2 − 3ab2

Mathematics

1 answer:

snow_lady [41]3 years ago

5 0

<span>4ab^2 − 3ab^2 = ab^2
combine like terms

help it helps</span>

You might be interested in

What are two decimals close two 6.3

WITCHER [35]

Answer:

6.2 and 6.4

Step-by-step explanation:

I am right please like

5 0

3 years ago

When calculating the circumference of a circle, sometimes the radius is given instead of the diameter. What is the relationship

Gwar [14]

The diameter is equal to the radius multiplied by 2.

3 0

3 years ago

4,12,36,108,324 identify the pattern

defon

Each number is being multiplied by 3.

4 0

3 years ago

Round each number to the nearest ten. What is the best estimate for the answer to 343.42 – 39.87?

Dafna11 [192]

The original answer for that question would be 303.55. The best estimate when you round to the nearest tenth the approximate answer would be 303.6 because the 5 in the hundredths place rounds the 5 in the tenths place to a 6. So the approximate answer would be 303.6....hope this helps.

3 0

3 years ago

Read 2 more answers

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

3 years ago