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KIM [24]
3 years ago
7

A 2-column table with 2 rows. Column 1 is labeled x with entries negative 7, 0. Column 2 is labeled y with entries 0, 1.

Mathematics
1 answer:
posledela3 years ago
3 0

Answer:

1/7 i took the assigmnet this was the awnser

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If y = 3ab + 2b3, what is y when a = 1 and b = 2
Dominik [7]

Answer:  The required value of y is 22.

Step-by-step explanation:  We are given the following function of a and b :

y=3ab+2b^3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the value of y when a = 1 and b = 2.

To find the required value of y, we need to substitute the values of a and b in equation (i).

From (i), we get

y=3\times1\times2+2\times2^3=6+16=22.

Thus, the required value of y is 22.

5 0
3 years ago
Pleaseeee help me solve this
Ulleksa [173]

Answer:

3/5 is the answer!

Step-by-step explanation:

y = 3x/5 also means y = 3/5 * x

Which means in y = mx form, the 3/5 = m

6 0
2 years ago
The coordinates (12.6) (12:10) (18.6) and (18.10) will be the comers of the floor for the sound
belka [17]

Answer:

matematik

Step-by-step explanation:

<em><u>gfdfhgychxbgegsxgftugnzefjhfhfbffhhfbccbhfhncncjfbcb</u></em><em><u> </u></em><em><u>cbbx</u></em><em><u> </u></em><em><u>bbffb</u></em><em><u>. </u></em><em><u>bfhkjvmvjjtgjfufjtjtjchuftugdvrhdhdhbfcbhfhbjhbuvgkh</u></em>

4 0
3 years ago
The table below shows the percentage of households that own a microwave in different countries. Construct a stem-and-leaf plot o
S_A_V [24]
Ya then 8 |8 8
then 6 |4 9
5 0
3 years ago
Help me guys <br> thx so much
navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
Read 2 more answers
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