A 2-column table with 2 rows. Column 1 is labeled x with entries negative 7, 0. Column 2 is labeled y with entries 0, 1.

A cell phone company offers service for a flat rate of 20$ per month,plus 3 cents a minute. Which expression could represent the

ElenaW [278]

Answer:

20 + 3x = x

Step-by-step explanation:

4 0

3 years ago

It costs $60.00 to rent the gymnasium, plus $5.00 per person. What would be the total cost to rent the gymnasium for 40 people?

qwelly [4]

$260.00
Because you won’t need to multiply the $60.00 per person

5 0

3 years ago

5x-11=3x+5 solve for ”x”

I am Lyosha [343]

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

5x - 11 = 3x + 5

Step 2: Solve for x

Subtract 3x on both sides: 2x - 11 = 5

Add 11 to both sides: 2x = 16

Divide both sides by 2: x = 8

Step 3: Check

Plug in x to verify it is a solution.

5(8) - 11 = 3(8) + 5

40 - 11 = 24 + 5

29 = 29

4 0

3 years ago

50 Points. what is the value of x

amm1812

Answer:

X will be = to 6°

Cause the lengths is 6

so 6 ×6° = 36°

I hope am wrong

7 0

3 years ago

Read 2 more answers

Jane’s buying clothes. She can get 5 shirts & 4 sweaters for $229 or she can get 2 shirts & 3 sweaters for $128. How muc

makkiz [27]

Cost of 1 shirt is $\$25$ and cost of one sweater is $\$26$

Solution:

Given that Jane’s buying clothes.

She can get 5 shirts & 4 sweaters for $\$229$

She can get 2 shirts & 3 sweaters for $\$128$

Need to determine cost of 1 shirt and 1 sweater.

Let assume cost of 1 shirt = $\$x$

And assume cost of 1 sweater = $\$y$

Let us create equations from give conditions

First condition is Cost of 5 shirt + cost of 4 sweater = $\$229$

$\begin{array}{l}{\text { cost of 5 shirts }=5 \times \text { cost of 1 shirt }=5 \times x=5 x} \\\\ {\text { cost of 4 sweater }=4 \times \text { cost of 1 sweater }=4 \times y=4 y}\end{array}$

So using first condition equation which we get is as follows

$5 x+4 y=229 \rightarrow (1)$

Second condition is Cost of 5 shirt + cost of 4 sweater = $\$128$

$\begin{array}{c}{\text { cost of } 2 \text { shirts }=2 \times \text { cost of } 1 \text { shirt }=2 \times x=2 x} \\\\ {\text { cost of } 3 \text { sweater }=3 \times \text { cost of } 1 \text { sweater }=3 \times y=3 y}\end{array}$

So using second condition equation which we get is as follows

$2 \mathrm{x}+3 \mathrm{y}=128\quad\rightarrow (2)$

Now we have two equations to be solved

$\begin{array}{l}{5 x+4 y=229 \rightarrow (1)} \\\\ {2 x+3 y=128 \rightarrow (2)}\end{array}$

On multiplying equation (1) by 2 and equation (2) by 5 to make coefficients of x equal in both equations, we get

$\begin{array}{l}{2 x(5 x+4 y)=2\times 229} \\\\ {10 x+8 y=458 \rightarrow (3)} \\\\ {5 x(2 x+3 y)=5 \times 128} \\\\ {10 x+15 y=640 \rightarrow (4)}\end{array}$

On subtracting (3) from (4), we get

$\begin{array}{l}{(10 \mathrm{x}-10 \mathrm{x})+(15 \mathrm{y}-8 \mathrm{y})=640-458} \\\\ {\Rightarrow 7 \mathrm{y}=182} \\\\ {\Rightarrow \mathrm{y}=\frac{182}{7}=26}\end{array}$

On substituting y = 26 in equation (1) we get

$\begin{array}{l}{\Rightarrow 5 \mathrm{x}+(4 \times 26)=229} \\\\ {\Rightarrow 5 \mathrm{x}=229-104} \\\\ {\Rightarrow 5 \mathrm{x}=125} \\\\ {\Rightarrow \mathrm{x}=\frac{125}{5}=25}\end{array}$

Cost of 1 shirt = $\$x = \$25$

Cost of 1 sweater = $\$y = \$26$

7 0

3 years ago