Answer:
a^2 + 2a + 2
Step-by-step explanation:
replace x with (a +1) everywhere in the equation
f(a+1) = (a+1)^2 + 1
➡
a^2 + 2a + 1 + 1
X= 100 would be the answer
It's D. That is the only true statement.
There is only one real root, at x=-2, so the polynomial describing this parabola has factors of (x+2) with multiplicity 2. The y-intercept tells you the vertical stretch is 1.
The factorization is y = (x +2)².