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3 years ago

Find the equation of the line shown in the graph. Write the equation in slope-intercept form.

Mathematics

1 answer:

Marysya12 [62]3 years ago

7 0

Answer:

y=-2x+6

Step-by-step explanation:

y=mx+b

b= y-intercept

b=6

m= slope

m=y2-y1/x2-x1

take 2 points from the graph

(-3,10) and (3,2)

2-10/3-(-3)

-8/6

-4/3

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$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind

$\bf f(x)=2^x\qquad 
\begin{cases}
g(x)=f(x+k)&k=5\\
\qquad\quad f(x+5)\\
\qquad \quad 2^{x+5}
\end{cases}$

notice, in g(x)

B = 1, no change from parent

C= +2

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